1 00:00:00,193 --> 00:00:01,515 - [Voiceover] Alright, now let's tackle part c. 2 00:00:01,515 --> 00:00:04,947 Use quantitative reasoning, including equations as needed, 3 00:00:04,947 --> 00:00:06,571 to develop an expression 4 00:00:06,571 --> 00:00:08,882 for the new final position of the block. 5 00:00:08,882 --> 00:00:12,027 Express your answer in terms of D. 6 00:00:12,027 --> 00:00:15,546 Alright, I'm gonna set up a little table here for part c. 7 00:00:15,546 --> 00:00:17,273 Oops, sorry about that. 8 00:00:17,273 --> 00:00:19,851 Sometimes my pen is not functioning properly. 9 00:00:19,851 --> 00:00:22,187 Alright so part c. 10 00:00:22,187 --> 00:00:24,002 Let me set up two scenarios. 11 00:00:24,002 --> 00:00:27,318 So I have scenario one. 12 00:00:27,318 --> 00:00:32,318 Scenario one, where we compress the spring, 13 00:00:32,822 --> 00:00:34,804 our delta x is equal to d, 14 00:00:34,804 --> 00:00:37,702 and then we have scenario two, 15 00:00:37,702 --> 00:00:42,702 scenario two, where we compress the spring by 16 00:00:43,071 --> 00:00:45,737 twice as much, is equal to two d, 17 00:00:45,737 --> 00:00:48,089 and let me set up my table now, 18 00:00:48,089 --> 00:00:53,089 so, just like that and like this, 19 00:00:53,203 --> 00:00:54,772 and let's just think about a few things. 20 00:00:54,772 --> 00:00:56,821 So the first thing I wanna think about is 21 00:00:56,821 --> 00:01:01,821 the potential energy, so the potential energy 22 00:01:02,022 --> 00:01:04,821 when the spring is compressed. 23 00:01:04,821 --> 00:01:09,821 So potential energy when spring compressed. 24 00:01:15,302 --> 00:01:19,870 When, I'll just write compressed, when compressed. 25 00:01:20,972 --> 00:01:24,555 Well in this scenario I'll call it the potential energy 26 00:01:24,555 --> 00:01:28,230 for scenario one, it's equal to one half times 27 00:01:28,230 --> 00:01:32,264 the spring constant, times how much we compress it squared. 28 00:01:32,264 --> 00:01:34,163 Now what about scenario two? 29 00:01:34,163 --> 00:01:37,702 This potential energy is going to be equal to 30 00:01:37,702 --> 00:01:41,246 one half times the spring constant, times how much 31 00:01:41,246 --> 00:01:44,446 we compress it, it's now twice as much, squared, 32 00:01:44,446 --> 00:01:47,758 well this is equal to one half times the spring constant, 33 00:01:47,758 --> 00:01:51,703 times four d squared, 34 00:01:52,743 --> 00:01:53,889 and I can out the four up front, 35 00:01:53,889 --> 00:01:58,854 this is equal to four times one half, four times one half, 36 00:02:00,492 --> 00:02:03,655 times our spring constant, times d squared, 37 00:02:03,655 --> 00:02:06,888 which is equal to four times the potential energy 38 00:02:06,888 --> 00:02:09,904 when we just compress the spring by d. 39 00:02:09,904 --> 00:02:11,772 So we already see a little bit of what we talked about 40 00:02:11,772 --> 00:02:14,888 in part b, you compress your spring twice as much, 41 00:02:14,888 --> 00:02:18,172 you're going to have four times the potential energy, 42 00:02:18,172 --> 00:02:20,551 because the potential energy doesn't grow proportionately 43 00:02:20,551 --> 00:02:24,004 with how much you compress it, it grows with the square 44 00:02:24,004 --> 00:02:26,855 of how much you compress it. 45 00:02:26,855 --> 00:02:30,738 Alright, now let's think about kinetic energy 46 00:02:32,799 --> 00:02:37,546 Kinetic energy when x is equal to zero, 47 00:02:41,682 --> 00:02:44,696 so right when the spring, when we lose contact 48 00:02:44,696 --> 00:02:46,447 with the spring, the spring is no longer pushing 49 00:02:46,447 --> 00:02:50,114 on the block, well our kinetic energy is going to be 50 00:02:50,114 --> 00:02:53,647 equal to what our potential energy was when the spring 51 00:02:53,647 --> 00:02:55,982 was actually compressed. 52 00:02:55,982 --> 00:02:58,447 Another way of thinking about it, all that potential energy 53 00:02:58,447 --> 00:03:00,914 has now been turned into kinetic energy. 54 00:03:00,914 --> 00:03:02,531 Now what about over here? 55 00:03:02,531 --> 00:03:05,381 Well, the kinetic energy in this scenario, 56 00:03:05,381 --> 00:03:08,349 like we just saw before, that's gonna be equal to the 57 00:03:08,349 --> 00:03:10,169 potential energy when the spring was compressed. 58 00:03:10,169 --> 00:03:13,682 All of that potential energy gets turned into kinetic energy 59 00:03:13,682 --> 00:03:17,284 and this is equal to four times u one, four times 60 00:03:17,284 --> 00:03:19,725 the potential energy in scenario one, which is the same 61 00:03:19,725 --> 00:03:23,482 thing as four times, which is equal to four times 62 00:03:23,482 --> 00:03:26,060 the kinetic energy in scenario one. 63 00:03:26,060 --> 00:03:28,373 So we have four times the kinetic energy. 64 00:03:28,373 --> 00:03:33,164 Four times kinetic energy, kinetic, kinetic energy. 65 00:03:36,783 --> 00:03:41,435 So then we have stopping distance, stopping, 66 00:03:42,545 --> 00:03:46,137 stopping distance. 67 00:03:47,021 --> 00:03:49,862 We know here this is three d and we know, 68 00:03:49,862 --> 00:03:53,829 and then we can say "What's this?", this question mark. 69 00:03:53,829 --> 00:03:56,148 Well let's just think a little bit about this. 70 00:03:56,148 --> 00:03:59,914 We know that if we have that kinetic energy 71 00:03:59,914 --> 00:04:01,692 at x equals zero, 72 00:04:01,692 --> 00:04:06,575 so we know that k one plus the work done by friction, 73 00:04:08,058 --> 00:04:10,834 so let me make it clear, this right over here, 74 00:04:10,834 --> 00:04:15,118 that is work done by friction, work done by friction, 75 00:04:16,702 --> 00:04:19,784 and it's gonna be negative work cause the force of friction 76 00:04:19,785 --> 00:04:23,986 is acting in the direction opposite of the change in x, 77 00:04:25,153 --> 00:04:29,202 so the kinetic energy plus the work done by friction 78 00:04:29,202 --> 00:04:32,084 is going to be equal to zero. 79 00:04:32,084 --> 00:04:35,293 This work cancels out all of this energy. 80 00:04:35,293 --> 00:04:38,569 When we think about it, it's turning it all into heat. 81 00:04:38,569 --> 00:04:41,120 And so let's think about what the work done by friction 82 00:04:41,120 --> 00:04:42,335 is equal to. 83 00:04:42,335 --> 00:04:46,851 Well the work done by friction is equal to, is equal to, 84 00:04:48,620 --> 00:04:53,536 the coefficient of friction times the mass of the block, 85 00:04:53,536 --> 00:04:58,018 times the gravitational field, times how far, 86 00:05:00,879 --> 00:05:03,253 over what distance that force, this right over here 87 00:05:03,253 --> 00:05:05,600 is the force of friction, times over what distance 88 00:05:05,600 --> 00:05:10,260 that force was applied, so times three d. 89 00:05:10,260 --> 00:05:12,428 And to be clear, this force is going in 90 00:05:12,428 --> 00:05:16,078 the opposite direction of our change in x, 91 00:05:16,078 --> 00:05:20,486 so because of that this will be a negative, 92 00:05:20,486 --> 00:05:25,034 and so we can say, we can say that the kinetic energy 93 00:05:25,910 --> 00:05:30,445 at x equals zero, and now I can just write it as minus 94 00:05:30,445 --> 00:05:33,761 mu, the coefficient of friction, times mass, times 95 00:05:33,761 --> 00:05:38,515 the gravitational field, times three d is equal to zero. 96 00:05:38,515 --> 00:05:41,053 We can add this to both sides and we can get 97 00:05:41,053 --> 00:05:45,806 k one is equal to mu times m times g times three d, 98 00:05:47,650 --> 00:05:49,902 and if you wanted to solve for distance here, 99 00:05:49,902 --> 00:05:53,366 you can divide both sides by the force of friction. 100 00:05:53,366 --> 00:05:56,684 So divide both sides by mu times m times g, and you get 101 00:05:56,684 --> 00:05:58,984 three d, and I'm just swapping the sides here, 102 00:05:58,984 --> 00:06:02,368 is going to be equal to the amount of kinetic energy we have 103 00:06:02,368 --> 00:06:06,866 right as x equals zero, divided by mu times m times g 104 00:06:08,685 --> 00:06:11,840 and you can just view this as the force of friction. 105 00:06:11,840 --> 00:06:13,333 The force, I'll just call it 106 00:06:13,333 --> 00:06:16,602 the force of friction right over there. 107 00:06:16,602 --> 00:06:18,518 So if you wanna figure out your stopping distance 108 00:06:18,518 --> 00:06:20,268 you just figure out your kinetic energy, 109 00:06:20,268 --> 00:06:23,082 right when you, right at x equals zero, 110 00:06:23,082 --> 00:06:26,365 right when you start entering into the frictiony part of 111 00:06:26,365 --> 00:06:29,402 your platform and then you divide that by 112 00:06:29,402 --> 00:06:31,226 the force of friction, and that will give you 113 00:06:31,226 --> 00:06:32,685 your distance traveled. 114 00:06:32,685 --> 00:06:37,000 So the distance here, distance, so I can just put some 115 00:06:39,082 --> 00:06:42,350 arrows right over here, our distance is going to be 116 00:06:42,350 --> 00:06:46,632 equal to k two divided by the force of, 117 00:06:48,901 --> 00:06:50,809 the force of friction. 118 00:06:50,809 --> 00:06:54,050 Well k two is equal to four times k one, 119 00:06:54,050 --> 00:06:57,420 is equal to four times k one. 120 00:06:57,420 --> 00:06:59,854 and our force of friction is going to be the same 121 00:06:59,854 --> 00:07:01,755 We have the same coefficient of friction, 122 00:07:01,755 --> 00:07:03,737 we have the same mass, we have the same 123 00:07:03,737 --> 00:07:07,937 gravitational field, so divided by force of friction, 124 00:07:07,937 --> 00:07:12,303 and this we already know, k one divided by force of friction 125 00:07:15,205 --> 00:07:19,838 is equal to three d, so this is all going to be equal to 126 00:07:19,838 --> 00:07:24,534 four, this is going to be four times three d, 127 00:07:26,074 --> 00:07:30,814 three d, which is equal to 12 d, 12 d. 128 00:07:31,807 --> 00:07:34,156 So this is all a mathematical way of saying 129 00:07:34,156 --> 00:07:36,776 you compress it twice as much, you're going to have 130 00:07:36,776 --> 00:07:38,687 four times the potential energy when your 131 00:07:38,687 --> 00:07:40,822 spring is compressed, which means you're going to have 132 00:07:40,822 --> 00:07:44,139 four times the kinetic energy at x equals zero, 133 00:07:44,139 --> 00:07:46,705 which means it is going to take, you're going to have 134 00:07:46,705 --> 00:07:49,622 four times the stopping distance, so instead of stopping 135 00:07:49,622 --> 00:07:53,822 at three d or in six d as what the student proposed, 136 00:07:53,822 --> 00:07:58,822 you are now stopping at 12 d, so that is 137 00:07:58,856 --> 00:08:01,406 our stopping distance. 138 00:08:01,406 --> 00:08:03,838 Did we answer all of, yeah we answered all of part c. 139 00:08:03,838 --> 00:08:06,572 Use quantitative reasoning, including equations as needed, 140 00:08:06,572 --> 00:08:08,906 to develop an expression for the new final position 141 00:08:08,906 --> 00:08:09,621 of the block. 142 00:08:09,621 --> 00:08:12,755 Express your answer in terms of d. 143 00:08:12,755 --> 00:00:00,000 Yep, feel good about that.