1 00:00:00,413 --> 00:00:02,818 - [Voiceover] Let's say I'm person A here in my ship 2 00:00:02,818 --> 00:00:05,882 traveling through the universe at a constant velocity, 3 00:00:05,882 --> 00:00:08,090 so that is person A right over there. 4 00:00:08,090 --> 00:00:10,333 Let me write it a little bit bigger. 5 00:00:12,004 --> 00:00:13,406 Person A. 6 00:00:13,406 --> 00:00:17,478 And let's say that I have a friend, Person B, 7 00:00:17,478 --> 00:00:19,183 and they are in another ship. 8 00:00:19,183 --> 00:00:21,878 And in my frame of reference, so this is Person B, 9 00:00:21,878 --> 00:00:25,438 in my frame of reference, they are traveling, 10 00:00:25,438 --> 00:00:28,094 so their velocity vector looks like this, 11 00:00:28,094 --> 00:00:31,854 they are traveling at 8/10 of the speed of light, 12 00:00:31,854 --> 00:00:35,247 0.8 c. 13 00:00:35,247 --> 00:00:36,456 And so once again this is all given 14 00:00:36,456 --> 00:00:39,929 in A's frame of reference and my frame of reference. 15 00:00:39,929 --> 00:00:42,013 Now the question I have for you is 16 00:00:42,013 --> 00:00:45,606 surely there must be some third party, 17 00:00:45,606 --> 00:00:50,575 let's call them C for convenience. 18 00:00:50,575 --> 00:00:52,569 Surely there must be some third party 19 00:00:52,569 --> 00:00:54,165 or some third party frame of reference 20 00:00:54,165 --> 00:00:56,696 that we could imagine it might be someone in some ship, 21 00:00:56,696 --> 00:01:00,214 where their velocity in my frame of reference 22 00:01:00,214 --> 00:01:03,696 is in between being stationary and traveling 23 00:01:03,696 --> 00:01:06,472 0.8 times the velocity of light. 24 00:01:06,472 --> 00:01:09,613 And even more, from their frame of reference, 25 00:01:09,613 --> 00:01:13,289 A and B should be leaving or going outward from them 26 00:01:13,289 --> 00:01:15,097 at the same velocity. 27 00:01:15,097 --> 00:01:16,615 So what am I talking about? 28 00:01:16,615 --> 00:01:19,203 So, this is... 29 00:01:20,261 --> 00:01:21,486 we're gonna call, 30 00:01:21,486 --> 00:01:22,876 I'll just call this the frame of reference. 31 00:01:22,876 --> 00:01:25,979 So this first row is A's frame of reference 32 00:01:25,979 --> 00:01:27,758 that we just described. 33 00:01:27,758 --> 00:01:31,212 And C is going to be going with some velocity, V, 34 00:01:31,212 --> 00:01:34,761 away from A. 35 00:01:34,761 --> 00:01:37,739 So some velocity, V, we haven't figured it out yet. 36 00:01:37,739 --> 00:01:40,111 Now let's think about C's frame of reference. 37 00:01:40,111 --> 00:01:44,065 So frame of reference C, so C and C's frame of reference 38 00:01:44,065 --> 00:01:46,231 is just going to be stationary, 39 00:01:46,231 --> 00:01:50,039 and we want to figure out a V so that A and B 40 00:01:50,039 --> 00:01:54,263 are moving away from C at the same velocity. 41 00:01:54,263 --> 00:01:59,114 So in this frame of reference, A will look like, 42 00:01:59,114 --> 00:02:02,778 A will look like it's moving to the left 43 00:02:02,778 --> 00:02:05,151 with a velocity of negative, 44 00:02:05,151 --> 00:02:06,702 here it's magnitude is the same, 45 00:02:06,702 --> 00:02:08,170 but just in the other direction. 46 00:02:08,170 --> 00:02:12,723 And B will also be moving away with velocity V. 47 00:02:12,723 --> 00:02:17,187 So B, right over here, is going to be moving away 48 00:02:17,187 --> 00:02:19,275 with velocity V. 49 00:02:19,275 --> 00:02:20,952 So this is a really interesting question. 50 00:02:20,952 --> 00:02:23,684 Can we figure out what V is going to be? 51 00:02:23,684 --> 00:02:25,736 If we were dealing with the Galilean world, 52 00:02:25,736 --> 00:02:28,134 you might say well V is just going to be half way 53 00:02:28,134 --> 00:02:29,652 in between these two things. 54 00:02:29,652 --> 00:02:31,383 If we were just on the highway in the Galilean 55 00:02:31,383 --> 00:02:35,423 or Newtonian world, and B is going 80 miles per hour, 56 00:02:35,423 --> 00:02:38,604 and A is stationary, well then if C goes half way, 57 00:02:38,604 --> 00:02:41,802 if C is going 40 miles per hour, then from C's point of view 58 00:02:41,802 --> 00:02:44,585 it looks like A is going backwards at 40 miles per hour, 59 00:02:44,585 --> 00:02:47,569 and it'll look like B is going forward at 40 miles per hour. 60 00:02:47,569 --> 00:02:49,981 But we know by now that we don't deal, 61 00:02:49,981 --> 00:02:53,257 we aren't living in a Newtonian or Galilean universe, 62 00:02:53,257 --> 00:02:57,351 we're living in one defined by special relativity. 63 00:02:57,351 --> 00:02:59,568 So I encourage you to pause the video 64 00:02:59,568 --> 00:03:02,883 and figure out what this in between frame of reference, 65 00:03:02,883 --> 00:03:06,278 what it's velocity needs to be relative to A. 66 00:03:06,278 --> 00:03:09,016 And I'll give you a hint, it's going to involve 67 00:03:09,016 --> 00:03:12,338 the Einstein Velocity Addition Formula. 68 00:03:12,338 --> 00:03:13,769 So let's work through this together. 69 00:03:13,769 --> 00:03:15,082 So I'm just gonna write down 70 00:03:15,082 --> 00:03:17,657 the Einstein Velocity Addition Formula. 71 00:03:17,657 --> 00:03:20,863 So it tells us that the change 72 00:03:20,863 --> 00:03:24,465 in x prime 73 00:03:24,465 --> 00:03:27,730 with respect to t prime is equal to 74 00:03:27,730 --> 00:03:29,969 u minus v 75 00:03:29,969 --> 00:03:33,238 over one minus uv 76 00:03:33,238 --> 00:03:35,422 over c squared. 77 00:03:35,422 --> 00:03:37,482 Now let's think about how we might apply it. 78 00:03:37,482 --> 00:03:39,606 And the trick here is to really think about it 79 00:03:39,606 --> 00:03:43,180 from C's frame of reference, 80 00:03:43,180 --> 00:03:46,461 it's to think about it from C's frame of reference. 81 00:03:46,461 --> 00:03:49,521 So if you think about it from C's frame of reference, 82 00:03:49,521 --> 00:03:54,062 you could say, you could say that v right over there, 83 00:03:54,062 --> 00:03:56,005 let me put this in a different color, 84 00:03:56,005 --> 00:03:59,967 you could say that v is the velocity 85 00:03:59,967 --> 00:04:03,022 that A is moving away from C at, 86 00:04:03,022 --> 00:04:07,989 so velocity A 87 00:04:07,989 --> 00:04:09,463 moving... 88 00:04:10,425 --> 00:04:13,324 from C. 89 00:04:13,324 --> 00:04:17,293 And then you could say that u 90 00:04:17,293 --> 00:04:19,863 is the velocity that B is moving from C. 91 00:04:19,863 --> 00:04:23,343 Remember, we're dealing in C's frame of reference. 92 00:04:23,343 --> 00:04:25,108 So velocity... 93 00:04:26,947 --> 00:04:30,011 velocity that B moving... 94 00:04:31,360 --> 00:04:32,594 from... 95 00:04:34,024 --> 00:04:36,772 from C, actually let me make everything upper case. 96 00:04:36,772 --> 00:04:38,831 This should be upper case A, 97 00:04:38,831 --> 00:04:40,873 and this should be upper case C. 98 00:04:40,873 --> 00:04:45,536 And in that case, what is delta x prime over delta t prime? 99 00:04:45,536 --> 00:04:49,572 Well, that would be the velocity that B is moving 100 00:04:49,572 --> 00:04:52,026 away from A in A's frame of reference. 101 00:04:52,026 --> 00:04:53,300 I know that this can get a little bit confusing, 102 00:04:53,300 --> 00:04:54,565 but I really want you to pause it, 103 00:04:54,565 --> 00:04:57,854 watch it in slow mo, really think about what we're doing. 104 00:04:57,854 --> 00:05:01,509 I'm kind of starting now, I know I started this video 105 00:05:01,509 --> 00:05:03,108 in A's frame of reference, and this is really 106 00:05:03,108 --> 00:05:05,764 the trick of the problem is I'm now shifting 107 00:05:05,764 --> 00:05:07,477 over to C's frame of reference. 108 00:05:07,477 --> 00:05:11,238 I'm like, okay, V is the velocity A is moving away from C, 109 00:05:11,238 --> 00:05:15,408 B is the velocity, or u is the velocity B is moving from C, 110 00:05:15,408 --> 00:05:17,797 and in that case we can view delta x prime 111 00:05:17,797 --> 00:05:21,520 over delta t prime as the velocity that B is moving 112 00:05:21,520 --> 00:05:24,956 away from A in A's frame of reference. 113 00:05:24,956 --> 00:05:27,422 So B moving... 114 00:05:28,685 --> 00:05:31,325 moving from A 115 00:05:31,325 --> 00:05:32,878 in A's frame of reference. 116 00:05:32,878 --> 00:05:37,046 So in A's reference. 117 00:05:37,046 --> 00:05:40,049 And both of these are in C's reference. 118 00:05:40,049 --> 00:05:41,601 So let me write that down. 119 00:05:41,601 --> 00:05:45,776 In C's reference, 120 00:05:45,776 --> 00:05:48,489 in C's 121 00:05:48,489 --> 00:05:52,438 in C's reference. 122 00:05:52,438 --> 00:05:53,596 I really want you to think about this, 123 00:05:53,596 --> 00:05:56,145 this is a little confusing, but hopefully this helps you 124 00:05:56,145 --> 00:05:59,090 appreciate how this Einstein Addition, Velocity Addition 125 00:05:59,090 --> 00:06:00,599 can be valuable. 126 00:06:00,599 --> 00:06:04,394 Well now, we can substitute what we know. 127 00:06:04,394 --> 00:06:07,875 We know the velocity B is moving away from A, 128 00:06:07,875 --> 00:06:10,740 it is 0.8 c. 129 00:06:10,740 --> 00:06:14,091 So we can write, we can write 130 00:06:14,091 --> 00:06:17,174 0.8 c 131 00:06:17,174 --> 00:06:19,626 is going to be equal to, 132 00:06:19,626 --> 00:06:23,635 is going to be equal to u, the velocity B is moving 133 00:06:23,635 --> 00:06:26,184 from C in C's frame of reference. 134 00:06:26,184 --> 00:06:28,110 Well we say that this is just going to be B, 135 00:06:28,110 --> 00:06:29,867 that's going to be a positive v. 136 00:06:29,867 --> 00:06:33,267 So that right over there is going to be a positive v. 137 00:06:34,357 --> 00:06:36,488 Let me do that in, 138 00:06:36,488 --> 00:06:38,001 let me do that in the same color. 139 00:06:38,001 --> 00:06:39,598 It's going to be a positive v. 140 00:06:39,598 --> 00:06:43,749 And then from that, we are going to subtract the velocity A 141 00:06:43,749 --> 00:06:47,230 is moving from C in C's frame of reference. 142 00:06:47,230 --> 00:06:50,906 So A is moving from C with the velocity negative v. 143 00:06:50,906 --> 00:06:53,302 I know it's kind of confusing to replace a v 144 00:06:53,302 --> 00:06:55,922 with a negative v, but this is a generalized formula, 145 00:06:55,922 --> 00:06:57,275 while this is the actually value 146 00:06:57,275 --> 00:06:59,037 that we're using in this case. 147 00:06:59,037 --> 00:07:02,871 So minus negative V all of that over 148 00:07:02,871 --> 00:07:06,791 all of that over one minus, 149 00:07:06,791 --> 00:07:11,736 all of that over one minus the velocity of u 150 00:07:11,736 --> 00:07:14,018 times the velocity of v, well, 151 00:07:14,018 --> 00:07:17,039 or that's just going to be, that's going to be v 152 00:07:17,039 --> 00:07:20,677 times negative v or negative v squared. 153 00:07:20,677 --> 00:07:24,007 So I'll just write that as negative v squared 154 00:07:24,007 --> 00:07:26,048 over c squared. 155 00:07:26,048 --> 00:07:27,436 And just like that we have set it up 156 00:07:27,436 --> 00:07:28,913 so we can solve for v. 157 00:07:28,913 --> 00:07:31,662 And the key realization is is that we said, 158 00:07:31,662 --> 00:07:34,285 "Okay, there must be some spaceship C 159 00:07:34,285 --> 00:07:36,169 "that defines a frame of reference 160 00:07:36,169 --> 00:07:39,432 "where A and B are moving away from it 161 00:07:39,432 --> 00:07:41,846 "with velocities of equal magnitude." 162 00:07:41,846 --> 00:07:43,359 And so we use that information 163 00:07:43,359 --> 00:07:45,406 to go into C's frame of reference 164 00:07:45,406 --> 00:07:48,279 and use the Einstein Velocity Addition Formula. 165 00:07:48,279 --> 00:07:51,385 But instead of knowing what, 166 00:07:51,385 --> 00:07:53,678 instead of knowing what these are, 167 00:07:53,678 --> 00:07:55,300 and then solving for this, 168 00:07:55,300 --> 00:07:57,066 we know what this is, and we're assuming 169 00:07:57,066 --> 00:07:58,908 that these two have the same magnitude, 170 00:07:58,908 --> 00:08:01,524 and we're able to solve for v. 171 00:08:01,524 --> 00:08:03,530 And so let's do that right now. 172 00:08:03,530 --> 00:08:05,166 In fact, I will do that in the next video, 173 00:08:05,166 --> 00:08:06,270 so that we will have enough time. 174 00:08:06,270 --> 00:08:07,664 And I encourage you to solve for v 175 00:08:07,664 --> 00:00:00,000 on your own before you watch the next video.