1 00:00:00,000 --> 00:00:00,560 2 00:00:00,560 --> 00:00:04,140 Let's do a slightly more involved Snell's law example. 3 00:00:04,140 --> 00:00:06,240 So I have this person over here, sitting 4 00:00:06,240 --> 00:00:08,510 at the edge of this pool. 5 00:00:08,510 --> 00:00:11,380 And they have a little laser pointer in their hand 6 00:00:11,380 --> 00:00:13,202 and they shine their laser pointer. 7 00:00:13,202 --> 00:00:14,660 So in their hand, where they shine, 8 00:00:14,660 --> 00:00:18,970 it's 1.7 meters above the surface of the pool. 9 00:00:18,970 --> 00:00:21,980 And they shine it so it travels 8.1 meters 10 00:00:21,980 --> 00:00:24,600 to touch the surface of the water. 11 00:00:24,600 --> 00:00:27,660 And then the light gets refracted inward. 12 00:00:27,660 --> 00:00:28,950 It's going to a slower medium. 13 00:00:28,950 --> 00:00:30,680 If you think about the car analogy, 14 00:00:30,680 --> 00:00:33,560 the outside tires get to stay outside a little bit longer, 15 00:00:33,560 --> 00:00:34,480 so they move faster. 16 00:00:34,480 --> 00:00:35,900 So it gets refracted inward. 17 00:00:35,900 --> 00:00:38,290 And then it hits the bottom of the pool 18 00:00:38,290 --> 00:00:40,220 at some point right over here. 19 00:00:40,220 --> 00:00:42,950 And the pool, they tell us, is three meters deep. 20 00:00:42,950 --> 00:00:50,000 What I want to figure out is how far away does this point hit. 21 00:00:50,000 --> 00:00:52,423 So what is this distance right over here? 22 00:00:52,423 --> 00:00:56,612 23 00:00:56,612 --> 00:00:58,070 And to figure that out, I just need 24 00:00:58,070 --> 00:01:00,249 to figure out what this distance is. 25 00:01:00,249 --> 00:01:02,790 I need to figure out what this distance is-- so this distance 26 00:01:02,790 --> 00:01:04,004 right over here. 27 00:01:04,004 --> 00:01:06,130 And then figure out what that distance is, and then 28 00:01:06,130 --> 00:01:06,870 add them up. 29 00:01:06,870 --> 00:01:09,980 So I can figure out this part-- trying 30 00:01:09,980 --> 00:01:12,280 to do it in a different color-- this part right 31 00:01:12,280 --> 00:01:13,860 until we hit the surface of the water 32 00:01:13,860 --> 00:01:16,180 and then figure out this incremental distance, just 33 00:01:16,180 --> 00:01:17,154 like that. 34 00:01:17,154 --> 00:01:18,820 And hopefully with a little trigonometry 35 00:01:18,820 --> 00:01:21,310 and maybe a little bit of Snell's law 36 00:01:21,310 --> 00:01:22,620 we'll be able to get there. 37 00:01:22,620 --> 00:01:24,760 So let's start on maybe what's the simplest thing. 38 00:01:24,760 --> 00:01:26,610 Let's just figure out this distance. 39 00:01:26,610 --> 00:01:29,360 And it looks like it will pay off later on, as well. 40 00:01:29,360 --> 00:01:31,950 So let's figure out this distance right over here. 41 00:01:31,950 --> 00:01:35,800 So just the distance along the surface of the water, 42 00:01:35,800 --> 00:01:37,860 to where the laser point actually 43 00:01:37,860 --> 00:01:39,810 starts touching the water. 44 00:01:39,810 --> 00:01:42,760 And this is just a straight up Pythagorean theorem problem. 45 00:01:42,760 --> 00:01:44,870 This is a right angle. 46 00:01:44,870 --> 00:01:46,540 This is the hypotenuse, over here. 47 00:01:46,540 --> 00:01:51,216 So this distance, let's call this distance x. 48 00:01:51,216 --> 00:01:54,030 x squared plus 1.7 meters squared 49 00:01:54,030 --> 00:01:56,227 is going to be equal to 8.1 squared-- just 50 00:01:56,227 --> 00:01:57,560 straight up Pythagorean theorem. 51 00:01:57,560 --> 00:02:01,620 So x squared plus 1.7 squared is going 52 00:02:01,620 --> 00:02:04,260 to be equal to 8.1 squared. 53 00:02:04,260 --> 00:02:07,140 Or we could subtract 1.7 squared from both sides. 54 00:02:07,140 --> 00:02:13,360 We get x squared is equal to 8.1 squared minus 1.7 squared. 55 00:02:13,360 --> 00:02:15,070 If we want to solve for x, x is going 56 00:02:15,070 --> 00:02:16,730 to be the positive square root of this, 57 00:02:16,730 --> 00:02:19,350 because we only care about positive distances. 58 00:02:19,350 --> 00:02:24,570 x is going to be equal to the principal root of 8.1 squared 59 00:02:24,570 --> 00:02:27,460 minus 1.7 squared. 60 00:02:27,460 --> 00:02:29,210 And let's get our calculator out for that. 61 00:02:29,210 --> 00:02:38,190 So x is going to be equal to the square root of 8.1 squared 62 00:02:38,190 --> 00:02:42,760 minus 1.7 squared. 63 00:02:42,760 --> 00:02:50,130 And I get 7.9-- looks about-- let me just round it, 7.92. 64 00:02:50,130 --> 00:02:53,900 So x is about 7.92, although we could save that number there, 65 00:02:53,900 --> 00:02:55,510 so we can get a more exact number. 66 00:02:55,510 --> 00:03:01,300 So this is equal to 7.92. 67 00:03:01,300 --> 00:03:02,440 That is x. 68 00:03:02,440 --> 00:03:05,160 Now, we just have to figure out this incremental distance right 69 00:03:05,160 --> 00:03:07,860 over here, add that to this x, and then we 70 00:03:07,860 --> 00:03:09,280 know this entire distance. 71 00:03:09,280 --> 00:03:11,210 So let's see how we can think about it. 72 00:03:11,210 --> 00:03:15,700 So let's think about what the incident angle is 73 00:03:15,700 --> 00:03:17,820 and then the angle of refraction is. 74 00:03:17,820 --> 00:03:20,560 So I've dropped a perpendicular to the interface, 75 00:03:20,560 --> 00:03:22,950 or to the surface. 76 00:03:22,950 --> 00:03:27,970 So our incident angle is this angle right over here. 77 00:03:27,970 --> 00:03:30,750 That is our incident angle. 78 00:03:30,750 --> 00:03:32,830 And remember, Snell's law-- we care 79 00:03:32,830 --> 00:03:34,220 about the sine of this angle. 80 00:03:34,220 --> 00:03:36,720 Actually, let me just write down what we want to care about. 81 00:03:36,720 --> 00:03:40,140 So we know this is our incident angle. 82 00:03:40,140 --> 00:03:43,540 This is our angle of refraction. 83 00:03:43,540 --> 00:03:46,000 We know that the index of refraction 84 00:03:46,000 --> 00:03:47,510 for this medium out here-- and this 85 00:03:47,510 --> 00:03:51,690 is air, so it's going to be the index of refraction for air-- 86 00:03:51,690 --> 00:03:57,790 times the sine of theta 1-- this is just Snell's law, 87 00:03:57,790 --> 00:04:00,200 so times our incident angle, right here-- 88 00:04:00,200 --> 00:04:03,350 is going to be equal to the index of refraction 89 00:04:03,350 --> 00:04:06,910 for the water-- and we'll put the values 90 00:04:06,910 --> 00:04:11,970 in the next step-- times the sine of theta 2-- times 91 00:04:11,970 --> 00:04:16,890 the sine of our refraction angle, sine of theta 2. 92 00:04:16,890 --> 00:04:20,100 Now, we know-- we can figure out these ends 93 00:04:20,100 --> 00:04:21,579 from this table right over here. 94 00:04:21,579 --> 00:04:24,220 I actually got this problem from ck12.org's flex book 95 00:04:24,220 --> 00:04:27,300 as well or at least the image for the problem. 96 00:04:27,300 --> 00:04:29,810 And so if we want to solve for theta 2-- 97 00:04:29,810 --> 00:04:32,174 or if we know theta 2, we could then solve for this. 98 00:04:32,174 --> 00:04:34,340 And we'll do that with a little bit of trigonometry. 99 00:04:34,340 --> 00:04:37,350 Actually we won't even have to-- if we know the sine of theta 2, 100 00:04:37,350 --> 00:04:40,370 we'll be able to solve for this. 101 00:04:40,370 --> 00:04:42,270 All right, we'll think about it either way. 102 00:04:42,270 --> 00:04:44,840 Actually, we'll just solve for this angle, 103 00:04:44,840 --> 00:04:47,200 and then if we know this angle, then we'll 104 00:04:47,200 --> 00:04:49,810 be able to use a little trigonometry to figure out 105 00:04:49,810 --> 00:04:51,352 this distance over here. 106 00:04:51,352 --> 00:04:53,560 So to solve for that angle, we can look up these two. 107 00:04:53,560 --> 00:04:55,380 And so we just have to figure out what this is. 108 00:04:55,380 --> 00:04:57,590 We need to figure out what the sine of theta 1 is. 109 00:04:57,590 --> 00:05:00,820 So let's put in all of the values. 110 00:05:00,820 --> 00:05:04,160 Our index of refraction of air is 1.00029. 111 00:05:04,160 --> 00:05:05,770 So let me put that in there. 112 00:05:05,770 --> 00:05:08,140 So that's this. 113 00:05:08,140 --> 00:05:13,144 So 1.00029 times the sine of theta. 114 00:05:13,144 --> 00:05:15,310 And you say, oh, how do we figure out sine of theta? 115 00:05:15,310 --> 00:05:17,170 We don't even know what that angle is. 116 00:05:17,170 --> 00:05:19,510 But remember, this is basic trigonometry. 117 00:05:19,510 --> 00:05:23,480 Remember "soh cah toa." 118 00:05:23,480 --> 00:05:25,257 Sine is opposite over hypotenuse. 119 00:05:25,257 --> 00:05:26,840 So if you have this angle here-- let's 120 00:05:26,840 --> 00:05:30,920 make it a part of a right triangle. 121 00:05:30,920 --> 00:05:33,550 So if you make that as part of a right triangle, opposite 122 00:05:33,550 --> 00:05:35,950 over hypotenuse-- it's the ratio of this side, 123 00:05:35,950 --> 00:05:39,827 it's the ratio of that distance to the hypotenuse. 124 00:05:39,827 --> 00:05:41,660 This distance over here we just figured out, 125 00:05:41,660 --> 00:05:43,368 it's the same as this distance down here. 126 00:05:43,368 --> 00:05:44,060 It's x. 127 00:05:44,060 --> 00:05:47,130 So this is 7.92. 128 00:05:47,130 --> 00:05:49,330 So the sine of theta 1 is going to be 129 00:05:49,330 --> 00:05:53,050 the opposite of the angle, opposite over the hypotenuse. 130 00:05:53,050 --> 00:05:55,920 That just comes from the definition of sine. 131 00:05:55,920 --> 00:05:59,380 So it's going to be times-- so this part right over here, sine 132 00:05:59,380 --> 00:06:01,930 of theta 1-- we don't have to know what theta 1 is. 133 00:06:01,930 --> 00:06:13,960 It's going to be 7.92 over 8.1. 134 00:06:13,960 --> 00:06:16,810 And that's going to be equal to the index of refraction 135 00:06:16,810 --> 00:06:18,100 of water. 136 00:06:18,100 --> 00:06:21,307 So that's index of water is 1.33-- so let 137 00:06:21,307 --> 00:06:22,640 me do that in a different color. 138 00:06:22,640 --> 00:06:26,060 So that's going to be-- no, I wanted to do a different color. 139 00:06:26,060 --> 00:06:29,900 So that's going to be-- let me do it in this dark blue. 140 00:06:29,900 --> 00:06:35,851 So that's going to be 1.33 times sine of theta 2. 141 00:06:35,851 --> 00:06:37,850 And so, if we want to solve for sine of theta 2, 142 00:06:37,850 --> 00:06:41,900 you just divide both sides of this equation by 1.33. 143 00:06:41,900 --> 00:06:42,650 So let's do that. 144 00:06:42,650 --> 00:06:43,650 So I'll do it over here. 145 00:06:43,650 --> 00:06:46,420 So if you divide both sides by 1.33, 146 00:06:46,420 --> 00:06:58,280 we get 1.00029 times 7.92 over 8.1, 147 00:06:58,280 --> 00:07:00,880 and we're also going to divide by 1.33. 148 00:07:00,880 --> 00:07:06,120 So we're also dividing by 1.33. 149 00:07:06,120 --> 00:07:08,940 That is going to be equal to this sine of theta 2. 150 00:07:08,940 --> 00:07:12,920 151 00:07:12,920 --> 00:07:15,050 So let's figure what that is. 152 00:07:15,050 --> 00:07:16,210 So let's do that. 153 00:07:16,210 --> 00:07:19,650 Get the calculator out. 154 00:07:19,650 --> 00:07:26,174 So we have 1.00029 times 7.92. 155 00:07:26,174 --> 00:07:28,340 Well, actually I could even say times second answer, 156 00:07:28,340 --> 00:07:30,250 if we want this exact value. 157 00:07:30,250 --> 00:07:32,750 That was the last-- so I'm going to do that-- second answer. 158 00:07:32,750 --> 00:07:35,570 So that's the actual precise, not even rounding. 159 00:07:35,570 --> 00:07:40,030 And then we want to divide by 1.33, that's this right here. 160 00:07:40,030 --> 00:07:45,460 And then we want to divide by 8.1, and we get that. 161 00:07:45,460 --> 00:07:48,890 And that's going to be equal to the sine of theta 2. 162 00:07:48,890 --> 00:07:51,997 So that's going to be equal to the sine of theta 2. 163 00:07:51,997 --> 00:07:53,080 So let me write this down. 164 00:07:53,080 --> 00:08:00,752 So we have 0.735 is equal to the sine of theta 2. 165 00:08:00,752 --> 00:08:02,210 Now, we could take the inverse sine 166 00:08:02,210 --> 00:08:04,540 of both sides of this equation to solve for theta 2. 167 00:08:04,540 --> 00:08:07,470 So we get theta 2 is equal to-- let's just take 168 00:08:07,470 --> 00:08:10,340 the inverse sine of this value. 169 00:08:10,340 --> 00:08:14,080 So I take the inverse sine of the value that we just had, 170 00:08:14,080 --> 00:08:16,510 so answer is just our last answer. 171 00:08:16,510 --> 00:08:19,570 And we have theta 2 being 47.3-- let's 172 00:08:19,570 --> 00:08:22,550 say rounded-- 47.34 degrees. 173 00:08:22,550 --> 00:08:29,200 So this is 47.34 degrees. 174 00:08:29,200 --> 00:08:34,299 So we were able to figure out what theta 2 is, 47.34 degrees. 175 00:08:34,299 --> 00:08:36,590 So now we just have to use a little bit of trigonometry 176 00:08:36,590 --> 00:08:41,058 to actually figure out this distance over here. 177 00:08:41,058 --> 00:08:44,490 Now what trig ratio involves-- so we know this angle. 178 00:08:44,490 --> 00:08:49,540 We want to figure out its opposite side, to that angle. 179 00:08:49,540 --> 00:08:51,420 And we know the adjacent side-- we 180 00:08:51,420 --> 00:08:52,900 know that this right here is 3. 181 00:08:52,900 --> 00:08:56,030 So what trig identity deals with opposite and adjacent? 182 00:08:56,030 --> 00:08:57,900 Well, tangent-- toa. 183 00:08:57,900 --> 00:09:00,740 Tangent is opposite over adjacent. 184 00:09:00,740 --> 00:09:05,230 So we know that the tangent of this angle right over here 185 00:09:05,230 --> 00:09:11,130 of 47.34 degrees is going to be equal to this opposite side 186 00:09:11,130 --> 00:09:15,110 over here-- so I'll call that y-- is going 187 00:09:15,110 --> 00:09:18,750 to equal y over our adjacent side. 188 00:09:18,750 --> 00:09:20,400 And that's just 3 meters. 189 00:09:20,400 --> 00:09:24,340 Or if we want to solve for y, we multiply 190 00:09:24,340 --> 00:09:26,330 both sides of this equation by 3. 191 00:09:26,330 --> 00:09:34,840 You get 3 times the tangent of 47.34 degrees is equal to y. 192 00:09:34,840 --> 00:09:36,890 So let's just get the calculator out. 193 00:09:36,890 --> 00:09:41,430 So 3 times the tangent of that 47.34 degrees-- 194 00:09:41,430 --> 00:09:45,170 I'll use the exact answer-- 3 times the tangent of that 195 00:09:45,170 --> 00:09:48,470 is 3.255. 196 00:09:48,470 --> 00:09:51,610 So this distance right here, y. 197 00:09:51,610 --> 00:09:52,990 And we're at the home stretch. 198 00:09:52,990 --> 00:09:58,660 y is equal to 3.255 meters. 199 00:09:58,660 --> 00:10:02,280 Now, our question was, what is this total distance? 200 00:10:02,280 --> 00:10:04,900 So it's going to be this distance, x, 201 00:10:04,900 --> 00:10:07,130 plus y, plus the 3.25. 202 00:10:07,130 --> 00:10:09,830 So x was 7.92. 203 00:10:09,830 --> 00:10:11,540 And I'll round here. 204 00:10:11,540 --> 00:10:16,090 So it's literally just going to be 7.92 plus our answer 205 00:10:16,090 --> 00:10:16,650 just now. 206 00:10:16,650 --> 00:10:19,270 207 00:10:19,270 --> 00:10:21,652 So we get about 11.18. 208 00:10:21,652 --> 00:10:24,110 Or maybe if we want to really round, or get the same number 209 00:10:24,110 --> 00:10:26,350 significant digits, maybe 11.2 meters. 210 00:10:26,350 --> 00:10:29,550 I'll just say 11.18 meters. 211 00:10:29,550 --> 00:10:34,820 So this right here, the distance that we wanted to figure out 212 00:10:34,820 --> 00:10:40,300 is the point on the bottom of the pool where the actual laser 213 00:10:40,300 --> 00:10:43,280 pointer actually hits the surface of the pool 214 00:10:43,280 --> 00:10:49,950 will be 11.18-- approximately, I'm 215 00:10:49,950 --> 00:10:54,320 rounding a little bit-- meters from this edge of the pool 216 00:10:54,320 --> 00:10:54,880 right there. 217 00:10:54,880 --> 00:10:55,990 Anyway, hopefully you found that useful. 218 00:10:55,990 --> 00:10:58,531 It's a little bit more involved than the Snell's law problem. 219 00:10:58,531 --> 00:11:00,790 But really the hard part was just in the trigonometry, 220 00:11:00,790 --> 00:11:03,080 recognizing that you didn't have to know this angle, 221 00:11:03,080 --> 00:11:04,590 because you have all the information 222 00:11:04,590 --> 00:11:05,726 for the sine of that angle. 223 00:11:05,726 --> 00:11:07,600 You could actually figure out that angle now. 224 00:11:07,600 --> 00:11:09,430 Now that you know its sine, you could figure out 225 00:11:09,430 --> 00:11:10,340 the inverse sine of that. 226 00:11:10,340 --> 00:11:11,589 But that's not even necessary. 227 00:11:11,589 --> 00:11:15,010 We know the sine of the angle using basic trigonometry. 228 00:11:15,010 --> 00:11:17,250 We can use that and Snell's law to figure out 229 00:11:17,250 --> 00:11:18,534 this angle right here. 230 00:11:18,534 --> 00:11:19,950 And then once you know this angle, 231 00:11:19,950 --> 00:11:21,420 use a little bit more trigonometry 232 00:11:21,420 --> 00:11:24,255 to figure out this incremental distance. 233 00:11:24,255 --> 00:00:00,000