In the last video we figured out that if we had a proton
coming into the right at a velocity of 6 times 10 to the
seventh meters per second.
So the magnitude of the velocity is 1/5
the speed of light.
And if it were to cross this magnetic field, we used this
formula to figure out that the magnitude of the force on this
proton would be 4.8 times 10 to the negative 12 newtons.
And then the direction, we used our right hand rule
because it's a cross product.
And we figured out that it would be perpendicular-- well,
it has to be perpendicular to both, because we're taking the
cross product-- and right when it enters, the net force will
be downwards.
But then think about what happens.
If you have a downward force right there, then the particle
will be deflected downward a little bit, so its velocity
vector will then look something like that.
But it's still in the magnetic field, right?
And not only is it still in the magnetic field, but since
the particle is still moving within the plane of your video
screen, it's still completely perpendicular to
the magnetic field.
And so the magnitude of the force on the moving particle
won't change, just the direction will.
Because if we do the right hand rule here, but if we just
move our hand down a little bit, if we tilt it down, then
our thumb's going to be pointing in this direction.
And that just keeps happening.
It gets deflected that way a little bit.
So the magnitude of the velocity doesn't ever change.
It always stays perpendicular to the magnetic field because
it's always staying in this plane.
But the orientation does change within the plane.
And because of that, because the orientation of the
velocity changes, the orientation
of the force changes.
So when the velocity is here, the force is perpendicular.
So it acts as kind of a centripetal force, and so the
particle will start moving in a circle.
So let's see if we can break out our toolkit from what
we've learned before in classical mechanics, and
figure out what the radius of that circle is.
And that might seem more daunting than it really is.
Well, what do we know about centripetal forces and
radiuses of circles, et cetera?
So, what is the formula for centripetal force?
And we proved it many, many videos ago, early in the
physics playlist. Well, centripetal acceleration is
the magnitude of the velocity vector squared over the radius
of the circle.
And since this is acceleration, if we want to
know the centripetal force, it's just the mass times
acceleration.
So it's the mass of the particle, or the object in
question, times the magnitude of its velocity squared
divided by the radius of the circle.
In this case, this is the radius of the circle.
And that's what we're going to try to solve for.
And what do we know about the centripetal force?
What is causing the centripetal force?
Well, it's the magnetic field and we've figured that out.
This is going to be equal to this, which we figured out is
going to be equal to-- at least the magnitudes-- the
magnitude of this is equal to the magnitude of this.
And that magnitude is 4.8 times 10 to
the minus 12 newtons.
And so the radius is going to be-- let's see, if we flip
both sides of this equation, we get radius over mass
velocity squared is equal to 1 over 4.8 times 10
to the minus 12.
I could just figure out what that number is, but I won't
worry about that now.
Then we can multiply both sides times this mv squared.
And we get that the radius of the circle is going to be
equal to the mass of the proton times the magnitude of
its velocity squared divided by the force from
the magnetic field.
The centripetal force.
4.8 times 10 to the minus 12 newtons.
And the radius should be in meters, since everything is
kind of in the standard SI units.
And let's see if we can figure this out.
Get our calculator.
And this is where that constant function is useful
again, because what is the mass of a proton?
Well, that's something that I
personally don't have memorized.
But if we go into the built-in constants on the
TI-85-- let's see more.
Mass of a proton.
This is mass of an electron.
This is mass of a proton.
So mass of a proton-- that's what we care about-- times the
magnitude of the velocity squared.
What was the velocity?
It was 6 times 10 to the seventh meters per second.
So times 6 times 10 to the seventh
meters per second squared.
And all of that divided by the magnitude of
the centripetal force.
Which is the force that's being generated by the
magnetic field.
That's 4.8 times 10 to the negative 12.
Divided by 4.8 E minus 12.
Let's see.
Hopefully we don't get something funky.
There we go.
That's actually a pretty neat number.
1.25 meters.
That's actually a number that we can imagine.
So if you have a proton going in this direction at 1/5 the
speed of light through a-- what'd I say it was?
It was a 0.5 tesla magnetic field, where the vectors are
pointing out of the video.
We have just shown that this proton will go in a circle of
radius 1.25 meters.
Which is neat because it's a number that I
can actually visualize.
And so this whole business of magnetic fields making charged
particles go into circles, this is one of the few times
that I can actually say has a direct application into things
that you've seen.
Namely, your TV.
Or at least the old-school TVs. The non-plasma or LCD
TVs, your cathode ray TVs, take advantage of this.
Where you essentially have a beam of
not protons but electrons.
And a magnet-- if you take apart a TV, which I don't
think you should do, because you're more likely to hurt
yourself because there's a vacuum in there that can
implode, and all that-- but essentially, you have a magnet
that deflects this electron beam and does it really fast
so it scans your entire screen of different intensities, and
that's what forms the image.
I won't go into that detail.
Maybe one day I'll do a whole video on how TVs work.
So that's one application of a magnetic field causing a beam
of charged particles to curve.
And then the other application, and this is
actually one where it's actually useful to make the
particle go in a circle, is these cyclotrons that you read
about, where they take these protons and they make them go
in circles really, really fast, and then
they smash them together.
Well, have you ever wondered, how do they even make a proton
go in a circle?
It's not like you could hold it and guide
it around in a circle.
Well, that's what they do.
They pass it through an appropriate strength magnetic
field, and it curves the path of the proton so that it can
keep going through the same field over and over again.
And then they can actually use those electric fields.
I don't claim to have any expertise in this, but then
they can keep speeding it up using the same devices,
because it keeps passing through the
same part of the collider.
And then once it collides, you've
probably seen those pictures.
You know, that you spend billions of dollars on
supercolliders, and you end up with these pictures.
And somehow these physicists are able to take these
pictures and say, oh, this is some new particle because of
the way it moved.
Well, what they're actually talking about is these are
moving at relativistic speeds.
And since they're at relativistic speeds as they
move at different velocities, their mass is
changing, and all that.
But the basic idea is what we just learned.
They move in circles.
They move in circles because they're going through a
magnetic field.
But their radiuses are different because their
charges and their velocities are going to be different.
And actually some will move to the left and some
will move to the right.
And that might be because they're positive or negative,
and then the radius will be dependent on their masses.
Anyway, I don't want to confuse you.
But I just wanted to show you that we actually are touching
on some physics that a physicist would
actually care about.
Now with that said, what would have happened if this wasn't a
proton but if this was an electron moving at this
velocity at 6 times 10 to the seventh meters per second
through a 0.5 tesla magnetic field
popping out of this video.
What would have happened?
Well, this formula would have still been safe.
The magnitude of the force is the charge-- but it wouldn't
have been the charge of a proton, it would have been the
charge of an electron, times 6 times 10 to the seventh meters
per second times 0.5 teslas.
So what's the difference between the charge of a proton
and the charge of an electron?
Well, the charge of an electron is negative.
So if this was an electron, then the net force would
actually end up being a negative number.
So what does that mean?
Well, when we used the right hand rule with the proton
example, we said that the-- at least when the proton is
moving in this direction-- that the net
force would be downwards.
But now, all of a sudden, if we reverse the charge, if we
say we have a negative charge-- the same magnitude
but it's negative, because it's an
electron-- what happens?
The force is now in this direction, using the right
hand rule, but it is a negative.
So really it's going to be a positive force of the same
magnitude in this direction.
So if we have a proton, it'll go in a
circle in this direction.
It'll go like this.
But if we have an electron, it'll go in a circle of the
other direction.
Now let me ask a question.
Is that circle going to be a tighter
circle or a wider circle?
Well, the mass of an electron is a lot smaller than the mass
of a proton.
And we had the radius is equal to the mass times the velocity
squared divided by the centripetal force.
So this mass is smaller and the radius
is going to be smaller.
So the electron's path would actually move up and it would
be a smaller radius.
Actually proportional to the difference in their radiuses
is the difference in their masses, actually.
But that would be the path of the electron.
Anyway, I thought you'd be interested in that, as well.
I have run out of time.
I will see you in the next video.