- [Instructor] So it turns out solving electric field
problems gets significantly harder
when there's multiple charges.
I mean, theoretically it shouldn't,
but people have a lot more problems
when there's multiple charges involved.
So say the question is this;
let's say we wanted to know what's the magnitude
and direction of the net electric field,
i.e. the total electric field,
created halfway between these two charges down here.
So you've got a positive eight nanocoulomb charge
and a negative eight nanocoulomb charge,
and they're separated by six meters
from the center to center distance.
But what we want to know is what's the total electric field
that they both create right there?
So each charge is going to create an electric field
at this point, and if you add up like vectors,
those electric fields, what total electric field
would you get?
Now at first you might think, well you should
just get zero, right?
It's very tempting to say that the electric field
is just gonna be zero there
because you've got a positive eight nanocoulomb charge
and a negative eight nanocoulomb charge
and those should just cancel, right?
But you have to be really careful,
turns out that's not true here,
this is not gonna be true.
And to see why, first you should just draw
what is the direction of each field at that point?
So this positive eight nanocoulomb charge is gonna
create a field at this point that goes radially away
from the positive charge, and so it's gonna go to the right.
And I'm not even looking, so when I'm trying to find
the electric field from this positive charge over here,
I'm not even paying attention to this negative charge,
I pretend like this negative charge
doesn't even exist.
Then I just ask what field would this
positive charge create?
It's still gonna create that field
whether this negative charge is over here or not.
And now I can do the same thing, I can ask
what field would this negative charge create?
And I'm gonna pretend like this positive charge
isn't even here.
So negative charges create a field that go radially in.
So over here radially in would point to the right.
So these don't cancel.
The negative charge created a field radially in,
that was to the right, the positive charge created a field
radially out of the positive charge,
and that was to the right.
So not only are these not gonna cancel,
these are gonna add up to twice the fields
cuz you're gonna add up these vectors,
you just add them up if they're in the same direction,
and you'll get two times the contribution
from one of them.
So it's not always the case, in other words
it's not always the case that a negative charge
and a positive charge have to cancel
their electric fields.
Those electric fields might point the same direction,
so you gotta be careful.
So how do we find this net electric field then,
what do we do?
Well we're gonna say that, all right, this electric field,
the first thing I can say is this net electric field
is just gonna point in the x direction.
So this is just really in the x direction,
all I really care about is the electric field
in this horizontal direction, and it's gonna be equal
to the sum of the electric fields
each charge creates there.
So we'll do the blue charge first, that's gonna be k
times the blue charge divided by r squared.
Then we'll do the yellow charge, it's gonna be
plus k, the charge of that yellow charge,
divided by r squared.
So we'll plug in some values here, this k is always
nine times 10 to the ninth,
and the q of this blue charge was positive eight
nanocoulombs, nano is 10 to the negative ninth,
I like using nano because then that negative nine
cancels with that positive nine.
And what distance do I put in here?
A lot of people wanna put in six,
but that's not what I want.
Think about it, I want the net electric field
halfway between the two charges,
so the r that I care about in this electric field formula
is the distance from the charge to the point
where I want to determine the electric field,
and in that case this is three meters.
So for this case, from the charge to the point
I'm concerned about finding the field
is three meters, not six meters.
If we were finding the force these charges exert
on each other, then I'd have to use six meters,
but that's not what I'm finding, I'm finding the field
each charge creates at this halfway point.
So I'm gonna plug in three meters down here,
and I can't forget to square it.
And now I have to be careful, just cuz my charge is positive
doesn't necessarily mean that the contribution
to the electric field is positive.
You have to check, you can't rely on the sign
of this charge to tell you whether the contribution's
positive or negative.
I've gotta look at what direction it points,
the direction this positive charge creates a field
is to the right.
Since that's typically the direction we call positive,
then I'm okay with calling this entire term here positive.
Then we're gonna have another term.
I'm gonna leave off the plus or minus cuz, I mean,
it might be plus, it might be minus,
we'll leave that off for a second,
we'll have to decide when we know what direction it goes.
So we do nine times 10 to the ninth,
and then the charge is negative eight nanocoulombs,
but I am not gonna plug in the negative sign.
Oops, and I left off coulomb on the other one here, sorry.
And then again, the distance I want is from the charge
to the point where we want to find the field,
and that again is three meters, and we can't forget
to square it.
So should this contribution be positive or negative?
I can't rely on the negative sign to tell me that,
I've gotta look at what direction it goes.
Since it goes to the right, that's the positive direction,
so this is gonna be plus, these add up,
these both go the same direction, the positive direction,
so the total net electric field is just gonna be
both of these added up.
So if I do this, if I square this three I'm getting nine,
and nine divided by nine is just one,
so I get eight newtons per coulomb,
and then this term is really the same thing,
nine is divided by nine so that goes away,
10 to the ninth cancels with 10 to the negative ninth
and all I'm left with is this eight,
so it'd be plus eight newtons per coulomb.
So each charge is contributing eight newtons per coulomb
of electric field at this point
which means that the total net electric field
would just be 16 newtons per coulomb at that point.
That is the net electric field, that's the magnitude
of the net electric field at that point between them.
And which way does it go, what's the direction?
It goes to the right cuz both of these vectors
pointed to the right so the total is gonna be
twice as big as one of them and also to the right.
Now if you have a case like this and both terms,
you know both terms are gonna be equal,
you can just write one of them down and multiply by two,
you don't have to just add them both up,
but I wanted to show you this way so you could see
how everything works out.
And in the end we get 16 newtons per coulomb
for the total field which points to the right.
Now what if we changed this, what if we made this
instead of a negative eight nanocoulomb charge
we made this a positive eight nanocoulomb charge?
Well it would no longer create an electric field
that points to the right.
Positive charges create fields that point radially
away from them, so it would create its electric field
to the left, which means down here when we find
its contribution to the electric field
we'd have to include it as a negative contribution
cuz it's pointing in the negative direction.
Even though it's a positive charge, the contribution
it gives to the total electric field is negative
cuz it points in the negative direction.
And that would give me zero, so if I had this a positive
this whole thing would add up to zero cuz I'd have eight
and then minus eight and I'd get zero
newtons per coulomb, so the electric field
would completely cancel right in the middle.
So what I'm saying is you have to be very careful
with your negative signs, don't just assume
these contributions are always gonna add up.
You can find each one always plugging in the charges
as positive even if they're negative
and then decide should I add or subtract
these contributions based on whether
they go to the right or to the left.
If they point to the right you'd choose a positive
in front of this term since it points
in the positive x direction.
And if they point to the left you're gonna choose
a negative in front of this term
because it would point in the negative x direction.
So recapping, to find the total electric field
from multiple charges, draw the electric field
each charge creates at the point where you want to
determine the total electric field,
use this formula to get the magnitude of the contribution
from each charge, then decide whether those contributions
should be positive or negative based not on the sign
of the charge but the direction the field is pointing
from that charge, add up the two contributions,
and that'll give you the total electric field
at that point.