- [Instructor] So in the previous video,
we defined all the new angular motion variables
and we made an argument that those are more useful
in many cases to use than the regular motion variables
for things that are rotating in a circle.
Since every point on the string in tennis ball,
let's say this is a tennis ball you tied a string to
and you're whirling around in a circle.
Every point on the string including the tennis ball
will have the same angular displacement,
angular velocity and angular acceleration.
But even though using angular motion variables
is more convenient for these rotational motion problems,
it's also really important to know
how to translate those angular motion variables
back into the regular motion variables.
So that's what I wanna show you in this video
how to translate angular motion variables
back into regular motion variables.
So let's do this.
The simplest possible angular motion variable
was the angular displacement
because that just represented
how much angle an object has rotated through.
So let's say it rotated through this much.
We represented the angular displacement with a delta theta
and we call it the angular displacement.
In Physics, we typically choose to measure this in radians
for a reason and I'll show you in just a second.
Now, how would we convert this
into a regular motion variable?
What regular motion variable would that be?
If I were to come at this for the first time,
I'd be like all right, this is the angular displacement.
Let's figure out how to relate it
to the regular displacement
but that would be weird.
Because just think about it,
the regular displacement for the ball
that started over here and made it over here
would be from this point to that point,
that would be the regular displacement of the ball,
the regular linear displacement of the ball.
That's a little weird.
I don't wanna show you how to find that
for one, you have to use the law of cosines.
That's a little more in depth
than I'd wanna get to in this video.
For two, the better reason
this isn't all that useful in turns out.
There's a much more useful quantity
that would tell you how far the ball went.
That's the arc length of the ball.
So the ball traced out of path through space
around the circle.
We call this the arc length that it turns out
this is much more useful in a variety of problems.
Good news is it's much easier to find
than that regular displacement.
So this is the arc length.
People vary on what letter to use here.
I've seen an l but most math books use s
so we'll just use s as well.
You might think this is hard to find but it's not.
In fact, if we use radians and this is why we use radians,
it's extremely easy to find.
If we wanted to find the arc length of this tennis ball,
we're just gonna take the radius of the circular path
that tennis ball is tracing out.
So in this case it'd be the length of the string.
We take that radius.
If we're in radians,
we just multiply by the angular displacement.
This is why the radians are so convenient.
We just take that measurement in radians
multiplied by the radius of the circular path
the object is tracing out.
You get the arc length which is the number of meters
along this path that the object has traveled.
If that seems miraculous, it really isn't.
I mean the reason why this works so well
because this is how the radian was defined.
One radian is defined to be the angle
through which you have to travel
so that the arc length is equal
to the radius of that circle.
So this isn't a surprise.
This was selected and defined strategically
so that we can use this unit
and we get a really easy way to convert
between the angular displacement,
how many radians something has rotated through,
and how many meters it has actually traveled
through its arc.
So this arc length is gonna have units of meters
as long as we measure the radius in meters.
All right, so that's one relationship
between angular displacement,
how much angles something has rotated through,
and how many meters it has actually traveled.
The next relationship I wanna talk about relates
the angular velocity to the regular velocity.
So remember in the previous video,
we defined the angular velocity
to be the angular displacement per times.
So this is the rate at which something is rotating
through a certain amount of angle
and the letter we use to represent velocity
was the Greek letter omega.
So this angular velocity represented the rate
at which something in a circle.
So it's rotating slowly.
It's gonna have a small angular velocity.
If it's rotating quickly,
it's gonna have a large angular velocity.
Obviously the speed and the angular velocity
are gonna be related because the higher
the angular velocity, the higher the speed.
But, what is that relationship?
How would we get from angular velocity
to the regular velocity?
Well it's not actually that hard at all
because all we need to do is turn this number
of radians per second into meters per second
and I can do that.
If multiply both sides of this equation down here by R,
I'll get R times omega is gonna equal
R times delta theta
and I still have to divide by delta t.
So you just multiply both sides of this equation by R.
But look what I get.
R times delta theta is just the arc length.
So this whole side over here is just
how many meters that object has traveled
around the edge of the circle
divided by the time that it took.
But that is just the speed.
This arc length is just the distance the object has traveled
and the time is the time that it took
and distance per time is just speed.
So this is the speed of the object.
I'm gonna write that as v
even though it's not velocity.
This is not a vector and it's not velocity
because think about it,
this arc length isn't displacement.
This was the distance the object traveled.
Distance per time is the speed.
Displacement per time is the velocity.
We didn't use displacement.
Displacement was this weird one.
We didn't wanna deal with that.
So since we're choosing to deal with arc length
which is distance, what we're gonna do is relate
the angular velocity into the speed.
Now we have that relationship.
Look at this.
This is R the radius times the angular velocity
equals the speed of the object.
So this is the relationship
between the angular velocity and the speed.
The speed of the object is gonna equal the radius
of the circular path the object is traveling in
times the angular velocity.
I should box these.
These are important.
This arc length formula was how you relate
the number of radians and object has rotated through
to how much arc length it's traveled,
i.e. how much distance it's gone through.
In this formula down here relates
the angular velocity omega,
the number of radians per second
something has rotating with
to how many meters per second it's traveling.
In other words, how many meters per second it's tracing out
along this arc length.
So this is good.
Now we know how to relate the angular displacement
to the distance the object has traveled
and we know how to relate the angular velocity
to the speed of the object
so you probably know what's coming next.
We have to relate the angular acceleration
to the regular acceleration.
So we're called that the angular acceleration
which we represented with a Greek letter alpha
was defined to be the change
in the angular velocity per times.
It's the rate at which your angular velocity was changing.
So there's moving at the constant rate.
You've got no angular acceleration
because there's no change in omega.
But if omega starts off slow
and then it gets faster and faster,
you do have angular acceleration.
It's probably not a surprise
that if you have angular acceleration,
this ball is gonna have regular acceleration too
because it's speeding up in its angular rotation.
It's gonna be changing its velocity as well.
So how do we this?
How do we relate the angular acceleration
to the regular acceleration?
Well the simplest thing to try is we go work down here.
We multiply both sides of our equation by the radius
and we found the relationship the related speed
to angular velocity.
So let's try it again.
Let's multiply both sides of this equation by radius
and see what we get.
On the left hand side, we can get the radius
times the angular acceleration.
That's gonna equal the radius times the change
in angular velocity over the change in time.
So all I've done here is multiply
both sides of this equation.
This definition of angular acceleration by the radius.
So let's see what we get on the right hand side.
We got R times delta omega.
So this is really R times the change in omega.
Well that's just omega final minus omega initial
and then divide it by delta t
so I can distribute this R and get that.
This would equal R times omega final
minus R times omega initial
divided by the time that it took.
But now look what happens.
We've got R times omega final and R times omega initial.
We know what R times omega is.
It's the speed, not the velocity, but the speed.
So I could rewrite this.
I could say that this is really the final speed
minus the initial speed over the time
that it took to change by that much speed.
So this is, if I just rewrite the left hand side,
this is what R times alpha is equal to.
Now if I were you, I'd be tempted to just be like,
oh look, we did it.
That's the acceleration which change in speed over time.
But you gotta be careful.
Acceleration, the true acceleration vector
is the change in velocity per time,
but these are not velocity vectors.
These were speeds.
So this isn't the true acceleration vector.
This is something different.
This is the change in speed per time.
So that's still an acceleration
but it's not necessarily the entire acceleration
because there's two ways to accelerate.
You can change your speed or change your direction.
Basically this acceleration we just found
doesn't take into account any acceleration
that's coming from changing your direction.
This is only the acceleration
that's gonna be changing your speed.
If I were you, I'd probably be confused at this point.
So let me try to show you what this means.
If this ball is rotating in a circle
just by the mere fact that the ball is rotating in a circle,
it has to be accelerating
even if the ball isn't speeding up or slowing down.
There's got to be an acceleration
because this ball is changing
the direction of its velocity.
These are gonna be a force.
It's centripetal force, in this case it would be detention.
There's gotta be a centripetal acceleration
that's changing the direction of the velocity.
That is not this acceleration over here.
This is a different acceleration.
We know the centripetal acceleration is directed inward.
We already know how to find this centripetal acceleration.
Remember the formula for centripetal acceleration
is the speed squared divided by the radius.
This component, this centripetal acceleration is
the component of the acceleration
that changes the direction of the velocity.
So I'm gonna say that again because this is important.
The centripetal acceleration which you can find
with v squared over R is the component of the acceleration
that changes the direction of the velocity.
If something is going in a circle,
it must have centripetal acceleration.
But this acceleration component
that we found down here is different.
This is what's changing the speed.
You don't have to have this if you're going in a circle.
You could imagine something going in a circle
at a constant rate.
If that's happening, it's got centripetal acceleration
but it doesn't have this thing down here
because this thing we found R times alpha
is the change in the speed of the object per time.
How would I draw that up here
if I wanted to represent this a
that we found down here visually up here?
I'd draw tangential to the direction of motion,
i.e. tangential to the circle
because components of acceleration
that are directed perpendicular to the velocity
change the direction of the velocity
but components of acceleration that are directed
parallel to the direction of the velocity change
the magnitude of the velocity, i.e. the speed,
to change the magnitude of the velocity,
in other words to speed something up or to slow it down.
You need a component of that acceleration
that's either in the directional motion
or opposite of the directional motion.
If it was opposite the directional motion,
the acceleration would be slowing the object down.
If the component of acceleration is in the direction
of motion, then it's speeding the object up.
That's what we found down here.
That's what this component of acceleration is,
R alpha which is why it's often called
the tangential acceleration.
So I'm gonna write that up here.
The tangential acceleration which is equal to R times alpha,
the radius times the angular acceleration
is the component of the acceleration
that's changing the magnitude of the velocity,
i.e. it's changing the speed.
In order to do that, it's gotta be directed
tangential to the direction of motion.
That's what this R times alpha represents.
So let me box that.
That's important.
This is the formula to find the tangential acceleration.
It doesn't give you the total acceleration.
We know that there's always a component of acceleration
that's acting centripetally
if an object is going in a circle
and you could that with v squared over R.
But if the object going in a circle is also speeding up
not only going in a circle but changing its speed,
it's gonna also have this component of acceleration
which is the tangential acceleration.
So at this point you might be confused
like wait, we've got tangential acceleration,
we've got centripetal.
Which one is the acceleration?
Well, they're both just components of the total acceleration
which you could find if you really wanted to.
You could say that the total acceleration squared.
You could use the Pythagorean theorem
because these are the two perpendicular components
of the total acceleration.
We said the total acceleration squared
would equal the tangential acceleration squared
plus the centripetal acceleration squared.
What we would be finding is the total acceleration squared
which if you wanted a direction,
the direction of that total acceleration
would point this way somewhere.
If you had centripetal acceleration inward
and let's say the object was speeding up.
So let's say it wasn't slowing down.
So you didn't have this component.
You've got this forwards component and inwards component.
The total acceleration would be directed here somewhere.
Since you could form a right triangle out of this
with these two sides, you can imagine moving
this centripetal acceleration over to this side
and you could find the hypothenuse
which would be the total acceleration
by just taking the tangential acceleration squared
plus the centripetal acceleration squared
and then taking a square root would give you
the magnitude of the total acceleration.
So recapping, there's two components of acceleration,
the tangential acceleration which is R times alpha,
either speeds an object up or slows it down,
the centripetal acceleration works to change
the direction of the motion of the object.
You can relate the speed of an object
to the angular velocity by multiplying by R.
You could relate the arc length, i.e. the distance
the object traveled around this edge of the circle
to the angular displacement by also multiplying by R.
So these three equations or how you relate
the angular motion variable to its linear counterpart.