1 00:00:00,000 --> 00:00:01,520 2 00:00:01,520 --> 00:00:03,270 I'm going to show you some examples of how 3 00:00:03,270 --> 00:00:05,380 to solve problems involving work. 4 00:00:05,380 --> 00:00:08,170 Imagine a 4 kilogram trashcan. 5 00:00:08,170 --> 00:00:09,860 The trashcan is disgusting. 6 00:00:09,860 --> 00:00:12,210 So someone ties a string to it and pulls 7 00:00:12,210 --> 00:00:14,630 on the string with a force of 50 newtons. 8 00:00:14,630 --> 00:00:17,920 The force of kinetic friction on the trashcan while it slides 9 00:00:17,920 --> 00:00:19,480 is 30 newtons. 10 00:00:19,480 --> 00:00:21,750 The trash can slides across the ground 11 00:00:21,750 --> 00:00:23,960 for a distance of 10 meters. 12 00:00:23,960 --> 00:00:27,510 Let's try to find the work done by each force on the trash can 13 00:00:27,510 --> 00:00:29,660 as it slides across the ground. 14 00:00:29,660 --> 00:00:31,830 To find the work done by each force, 15 00:00:31,830 --> 00:00:35,026 we should recall the formula definition of work. 16 00:00:35,026 --> 00:00:37,910 Work equals Fd cosine theta, where 17 00:00:37,910 --> 00:00:40,240 theta is the angle between the force doing 18 00:00:40,240 --> 00:00:43,250 the work and the direction the trashcan is moving. 19 00:00:43,250 --> 00:00:46,290 There are four forces involved here-- tension, 20 00:00:46,290 --> 00:00:48,930 the normal force, the gravitational force, 21 00:00:48,930 --> 00:00:50,730 and the force of kinetic friction. 22 00:00:50,730 --> 00:00:53,610 In finding the work done for all of these forces, 23 00:00:53,610 --> 00:00:55,950 the displacement is going to be 10 meters. 24 00:00:55,950 --> 00:00:58,190 But the value of the force and the angle 25 00:00:58,190 --> 00:01:00,460 between that force and the displacement 26 00:01:00,460 --> 00:01:02,750 is going to differ for each of the forces. 27 00:01:02,750 --> 00:01:06,090 For instance, to find the work done by the force of tension, 28 00:01:06,090 --> 00:01:09,530 we'll plug in the size of the tension, which is 50 newtons. 29 00:01:09,530 --> 00:01:11,620 The displacement is 10 meters. 30 00:01:11,620 --> 00:01:13,630 And since the tension force is pointed 31 00:01:13,630 --> 00:01:16,100 in the same direction as the displacement, 32 00:01:16,100 --> 00:01:19,220 the angle between the force of tension and the displacement 33 00:01:19,220 --> 00:01:20,720 is 0 degrees. 34 00:01:20,720 --> 00:01:24,605 And since cosine of 0 is 1, the work done by the tension force 35 00:01:24,605 --> 00:01:26,530 is 500 joules. 36 00:01:26,530 --> 00:01:28,370 To find the work done by friction, 37 00:01:28,370 --> 00:01:30,430 we'll plug in the size of the force of friction, 38 00:01:30,430 --> 00:01:31,860 which is 30 newtons. 39 00:01:31,860 --> 00:01:34,190 The displacement is still 10 meters. 40 00:01:34,190 --> 00:01:36,120 And since the force of friction points 41 00:01:36,120 --> 00:01:38,890 in the opposite direction as the displacement, 42 00:01:38,890 --> 00:01:41,740 the angle between the force of friction and the displacement 43 00:01:41,740 --> 00:01:43,670 is 180 degrees. 44 00:01:43,670 --> 00:01:46,660 Since cosine of 180 is negative 1, 45 00:01:46,660 --> 00:01:48,700 the work done by the force of friction 46 00:01:48,700 --> 00:01:51,120 is negative 300 joules. 47 00:01:51,120 --> 00:01:52,700 Now let's figure out the work done 48 00:01:52,700 --> 00:01:54,510 by the gravitational force. 49 00:01:54,510 --> 00:01:56,890 The force of gravity is mg. 50 00:01:56,890 --> 00:01:59,330 So the force of gravity is 4 kilograms 51 00:01:59,330 --> 00:02:04,600 times 9.8 meters per second squared, which is 39.2 newtons. 52 00:02:04,600 --> 00:02:07,120 The displacement is again 10 meters. 53 00:02:07,120 --> 00:02:09,699 But the angle between the gravitational force 54 00:02:09,699 --> 00:02:11,530 and the direction of the displacement 55 00:02:11,530 --> 00:02:13,630 is 90 degrees in this case. 56 00:02:13,630 --> 00:02:17,700 And since cosine of 90 is 0, the gravitational force 57 00:02:17,700 --> 00:02:19,810 does no work on this trashcan. 58 00:02:19,810 --> 00:02:22,000 Similarly, if we were to find the work done 59 00:02:22,000 --> 00:02:25,180 by the normal force, the angle between the direction 60 00:02:25,180 --> 00:02:28,340 of the displacement and the normal force is 90 degrees. 61 00:02:28,340 --> 00:02:31,900 So the normal force also does no work on the trashcan. 62 00:02:31,900 --> 00:02:33,700 This makes sense because forces that 63 00:02:33,700 --> 00:02:36,060 are perpendicular to the motion can never 64 00:02:36,060 --> 00:02:37,930 do any work on that object. 65 00:02:37,930 --> 00:02:41,500 So that's how you can find the work done by individual forces. 66 00:02:41,500 --> 00:02:44,510 And if we wanted to know the net work done on this trashcan, 67 00:02:44,510 --> 00:02:47,930 we could just add up the work done by each individual force. 68 00:02:47,930 --> 00:02:51,190 So the net work is going to be 200 joules. 69 00:02:51,190 --> 00:02:53,420 Now that we know the net work done on the trashcan, 70 00:02:53,420 --> 00:02:55,960 we can use the work-energy principle 71 00:02:55,960 --> 00:02:58,080 to figure out the speed of the trashcan 72 00:02:58,080 --> 00:03:00,240 after it's slid the 10 meters. 73 00:03:00,240 --> 00:03:03,040 The work-energy principle says that the net work done 74 00:03:03,040 --> 00:03:05,050 on an object is equal to the change 75 00:03:05,050 --> 00:03:06,980 in kinetic energy of that object. 76 00:03:06,980 --> 00:03:09,330 So 200 joules is going to equal the difference 77 00:03:09,330 --> 00:03:10,630 in kinetic energy. 78 00:03:10,630 --> 00:03:12,440 If we assume the trashcan started 79 00:03:12,440 --> 00:03:16,430 at rest, which seems reasonable, the initial velocity is 0. 80 00:03:16,430 --> 00:03:19,660 So we can solve for the final speed of the trashcan, which 81 00:03:19,660 --> 00:03:22,570 comes out to be 10 meters per second. 82 00:03:22,570 --> 00:03:24,640 This time, let's say you take the trashcan 83 00:03:24,640 --> 00:03:27,740 and lift it upwards with a constant velocity 84 00:03:27,740 --> 00:03:29,650 for a distance of 2 meters. 85 00:03:29,650 --> 00:03:33,130 In order to lift the trashcan up with a constant velocity, 86 00:03:33,130 --> 00:03:35,460 you need to push with a force equal to the weight 87 00:03:35,460 --> 00:03:38,210 of the trashcan, which means you have to push upwards 88 00:03:38,210 --> 00:03:41,030 with a force of 39.2 newtons. 89 00:03:41,030 --> 00:03:43,860 So to find the work done by the force that you exert, 90 00:03:43,860 --> 00:03:46,720 the force is going to be 39.2 newtons. 91 00:03:46,720 --> 00:03:49,190 The displacement is going to be 2 meters. 92 00:03:49,190 --> 00:03:52,040 And the angle between the force and the displacement 93 00:03:52,040 --> 00:03:55,060 is going to be 0 degrees because the direction of the force 94 00:03:55,060 --> 00:03:58,290 that you exert is in the same direction as the displacement 95 00:03:58,290 --> 00:03:59,440 of the trashcan. 96 00:03:59,440 --> 00:04:02,240 So the work that you've done in lifting up this 4 kilogram 97 00:04:02,240 --> 00:04:05,830 trashcan is 78.4 joules. 98 00:04:05,830 --> 00:04:08,200 To find the work done by the force of gravity, 99 00:04:08,200 --> 00:04:12,160 we can use the force of gravity, which is again 39.2 newtons. 100 00:04:12,160 --> 00:04:14,490 The displacement is again 2 meters. 101 00:04:14,490 --> 00:04:16,230 But the angle between the direction 102 00:04:16,230 --> 00:04:18,779 of the displacement and the gravitational force 103 00:04:18,779 --> 00:04:22,360 is 180 degrees because the displacement points up 104 00:04:22,360 --> 00:04:24,820 and the gravitational force points down. 105 00:04:24,820 --> 00:04:27,120 So the work done by the gravitational force 106 00:04:27,120 --> 00:04:30,560 is negative 78.4 joules, which means 107 00:04:30,560 --> 00:04:33,760 the net work done on the trashcan is 0. 108 00:04:33,760 --> 00:04:34,790 And that makes sense. 109 00:04:34,790 --> 00:04:38,760 Because since the trashcan moved upwards with constant velocity, 110 00:04:38,760 --> 00:04:42,975 there was no change in the kinetic energy of this object. 111 00:04:42,975 --> 00:00:00,000