1 00:00:00,000 --> 00:00:00,000 2 00:00:00,000 --> 00:00:01,580 Welcome back. 3 00:00:01,580 --> 00:00:03,540 I'll now do another conservation of energy 4 00:00:03,540 --> 00:00:06,110 problem, and this time I'll add another twist. So far, 5 00:00:06,110 --> 00:00:08,530 everything we've been doing, energy was conserved by the 6 00:00:08,530 --> 00:00:09,970 law of conservation. 7 00:00:09,970 --> 00:00:11,740 But that's because all of the forces that were acting in 8 00:00:11,740 --> 00:00:13,810 these systems were conservative forces. 9 00:00:13,810 --> 00:00:15,750 And now I'll introduce you to a problem that has a little 10 00:00:15,750 --> 00:00:17,810 bit of friction, and we'll see that some of that energy gets 11 00:00:17,810 --> 00:00:18,720 lost to friction. 12 00:00:18,720 --> 00:00:20,340 And we can think about it a little bit. 13 00:00:20,340 --> 00:00:22,470 Well where does that energy go? 14 00:00:22,470 --> 00:00:23,980 And I'm getting this problem from the University of 15 00:00:23,980 --> 00:00:25,230 Oregon's zebu.uoregon.edu. 16 00:00:25,230 --> 00:00:27,990 17 00:00:27,990 --> 00:00:30,590 And they seem to have some nice physics problems, so I'll 18 00:00:30,590 --> 00:00:31,120 use theirs. 19 00:00:31,120 --> 00:00:32,530 And I just want to make sure they get credit. 20 00:00:32,530 --> 00:00:32,860 So let's see. 21 00:00:32,860 --> 00:00:35,910 They say a 90 kilogram bike and rider. 22 00:00:35,910 --> 00:00:38,725 So the bike and rider combined are 90 kilograms. So let's 23 00:00:38,725 --> 00:00:45,920 just say the mass is 90 kilograms. Start at rest from 24 00:00:45,920 --> 00:00:48,840 the top of a 500 meter long hill. 25 00:00:48,840 --> 00:00:50,860 OK, so I think they mean that the hill is 26 00:00:50,860 --> 00:00:51,710 something like this. 27 00:00:51,710 --> 00:00:57,550 So if this is the hill, that the hypotenuse here is 500 28 00:00:57,550 --> 00:00:58,270 hundred meters long. 29 00:00:58,270 --> 00:01:04,160 So the length of that, this is 500 meters. 30 00:01:04,160 --> 00:01:07,420 A 500 meter long hill with a 5 degree incline. 31 00:01:07,420 --> 00:01:08,670 So this is 5 degrees. 32 00:01:08,670 --> 00:01:11,850 33 00:01:11,850 --> 00:01:14,370 And we can kind of just view it like a wedge, like we've 34 00:01:14,370 --> 00:01:18,070 done in other problems. There you go. 35 00:01:18,070 --> 00:01:20,890 That's pretty straight. 36 00:01:20,890 --> 00:01:22,550 OK. 37 00:01:22,550 --> 00:01:26,050 Assuming an average friction force of 60 newtons. 38 00:01:26,050 --> 00:01:28,490 OK, so they're not telling us the coefficient of friction 39 00:01:28,490 --> 00:01:29,580 and then we have to figure out the normal 40 00:01:29,580 --> 00:01:30,620 force and all of that. 41 00:01:30,620 --> 00:01:33,630 They're just telling us, what is the drag of friction? 42 00:01:33,630 --> 00:01:36,430 Or how much is actually friction acting against this 43 00:01:36,430 --> 00:01:38,750 rider's motion? 44 00:01:38,750 --> 00:01:40,360 We could think a little bit about where that friction is 45 00:01:40,360 --> 00:01:40,880 coming from. 46 00:01:40,880 --> 00:01:46,660 So the force of friction is equal to 60 newtons And of 47 00:01:46,660 --> 00:01:49,030 course, this is going to be going against his motion or 48 00:01:49,030 --> 00:01:50,040 her motion. 49 00:01:50,040 --> 00:01:53,150 And the question asks us, find the speed of the biker at the 50 00:01:53,150 --> 00:01:54,110 bottom of the hill. 51 00:01:54,110 --> 00:01:58,510 So the biker starts up here, stationary. 52 00:01:58,510 --> 00:01:59,240 That's the biker. 53 00:01:59,240 --> 00:02:01,560 My very artful rendition of the biker. 54 00:02:01,560 --> 00:02:05,230 And we need to figure out the velocity at the bottom. 55 00:02:05,230 --> 00:02:07,920 This to some degree is a potential energy problem. 56 00:02:07,920 --> 00:02:11,380 57 00:02:11,380 --> 00:02:14,790 It's definitely a conservation of mechanical energy problem. 58 00:02:14,790 --> 00:02:17,610 So let's figure out what the energy of the system is when 59 00:02:17,610 --> 00:02:19,550 the rider starts off. 60 00:02:19,550 --> 00:02:21,360 So the rider starts off at the top of this hill. 61 00:02:21,360 --> 00:02:23,930 So definitely some potential energy. 62 00:02:23,930 --> 00:02:26,850 And is stationary, so there's no kinetic energy. 63 00:02:26,850 --> 00:02:28,760 So all of the energy is potential, and what is the 64 00:02:28,760 --> 00:02:29,600 potential energy? 65 00:02:29,600 --> 00:02:35,030 Well potential energy is equal to mass times the acceleration 66 00:02:35,030 --> 00:02:37,950 of gravity times height, right? 67 00:02:37,950 --> 00:02:41,300 Well that's equal to, if the mass is 90, the acceleration 68 00:02:41,300 --> 00:02:43,830 of gravity is 9.8 meters per second squared. 69 00:02:43,830 --> 00:02:44,540 And then what's the height? 70 00:02:44,540 --> 00:02:45,960 Well here we're going to have to break out a little 71 00:02:45,960 --> 00:02:46,810 trigonometry. 72 00:02:46,810 --> 00:02:51,010 We need to figure out this side of this triangle, if you 73 00:02:51,010 --> 00:02:53,270 consider this whole thing a triangle. 74 00:02:53,270 --> 00:02:53,630 Let's see. 75 00:02:53,630 --> 00:02:55,080 We want to figure out the opposite. 76 00:02:55,080 --> 00:02:58,630 We know the hypotenuse and we know this angle here. 77 00:02:58,630 --> 00:03:01,920 So the sine of this angle is equal to opposite over 78 00:03:01,920 --> 00:03:03,440 hypotenuse. 79 00:03:03,440 --> 00:03:04,680 So, SOH. 80 00:03:04,680 --> 00:03:06,910 Sine is opposite over hypotenuse. 81 00:03:06,910 --> 00:03:10,490 So we know that the height-- so let me do a little work 82 00:03:10,490 --> 00:03:15,010 here-- we know that sine of 5 degrees is equal to 83 00:03:15,010 --> 00:03:17,510 the height over 500. 84 00:03:17,510 --> 00:03:25,420 Or that the height is equal to 500 sine of 5 degrees. 85 00:03:25,420 --> 00:03:28,470 And I calculated the sine of 5 degrees ahead of time. 86 00:03:28,470 --> 00:03:30,380 Let me make sure I still have it. 87 00:03:30,380 --> 00:03:32,820 That's cause I didn't have my calculator with me today. 88 00:03:32,820 --> 00:03:34,290 But you could do this on your own. 89 00:03:34,290 --> 00:03:38,400 So this is equal to 500, and the sine of 90 00:03:38,400 --> 00:03:42,806 5 degrees is 0.087. 91 00:03:42,806 --> 00:03:46,870 So when you multiply these out, what do I get? 92 00:03:46,870 --> 00:03:49,220 I'm using the calculator on Google actually. 93 00:03:49,220 --> 00:03:52,400 500 times sine. 94 00:03:52,400 --> 00:03:54,670 You get 43.6. 95 00:03:54,670 --> 00:03:58,900 So this is equal to 43.6. 96 00:03:58,900 --> 00:04:03,970 So the height of the hill is 43.6 meters. 97 00:04:03,970 --> 00:04:06,390 So going back to the potential energy, we have the mass times 98 00:04:06,390 --> 00:04:07,850 the acceleration of gravity times the height. 99 00:04:07,850 --> 00:04:09,740 Times 43.6. 100 00:04:09,740 --> 00:04:12,290 And this is equal to, and then I can use just my regular 101 00:04:12,290 --> 00:04:13,640 calculator since I don't have to figure out 102 00:04:13,640 --> 00:04:15,090 trig functions anymore. 103 00:04:15,090 --> 00:04:25,380 So 90-- so you can see the whole thing-- times 9.8 times 104 00:04:25,380 --> 00:04:34,860 43.6 is equal to, let's see, roughly 38,455. 105 00:04:34,860 --> 00:04:42,180 So this is equal to 38,455 joules or newton meters. 106 00:04:42,180 --> 00:04:44,270 And that's a lot of potential energy. 107 00:04:44,270 --> 00:04:44,980 So what happens? 108 00:04:44,980 --> 00:04:47,690 At the bottom of the hill-- sorry, I have to readjust my 109 00:04:47,690 --> 00:04:52,070 chair-- at the bottom of the hill, all of this gets 110 00:04:52,070 --> 00:04:53,590 converted to, or maybe I should 111 00:04:53,590 --> 00:04:54,260 pose that as a question. 112 00:04:54,260 --> 00:04:57,450 Does all of it get converted to kinetic energy? 113 00:04:57,450 --> 00:05:00,560 Almost. We have a force of friction here. 114 00:05:00,560 --> 00:05:03,880 And friction, you can kind of view friction as something 115 00:05:03,880 --> 00:05:08,120 that eats up mechanical energy. 116 00:05:08,120 --> 00:05:10,250 These are also called nonconservative forces because 117 00:05:10,250 --> 00:05:12,590 when you have these forces at play, all of the 118 00:05:12,590 --> 00:05:14,580 force is not conserved. 119 00:05:14,580 --> 00:05:19,160 So a way to think about it is, is that the energy, let's just 120 00:05:19,160 --> 00:05:20,430 call it total energy. 121 00:05:20,430 --> 00:05:30,670 So let's say total energy initial, well let me just 122 00:05:30,670 --> 00:05:40,740 write initial energy is equal to the energy wasted in 123 00:05:40,740 --> 00:05:51,870 friction-- I should have written just letters-- from 124 00:05:51,870 --> 00:06:00,170 friction plus final energy. 125 00:06:00,170 --> 00:06:03,670 So we know what the initial energy is in this system. 126 00:06:03,670 --> 00:06:07,120 That's the potential energy of this bicyclist and this 127 00:06:07,120 --> 00:06:12,730 roughly 38 and 1/2 kilojoules or 38,500 joules, roughly. 128 00:06:12,730 --> 00:06:17,530 And now let's figure out the energy wasted from friction, 129 00:06:17,530 --> 00:06:20,110 and the energy wasted from friction is the negative work 130 00:06:20,110 --> 00:06:20,850 that friction does. 131 00:06:20,850 --> 00:06:22,470 And what does negative work mean? 132 00:06:22,470 --> 00:06:29,000 Well the bicyclist is moving 500 meters in this direction. 133 00:06:29,000 --> 00:06:30,740 So distance is 500 meters. 134 00:06:30,740 --> 00:06:33,050 But friction isn't acting along the same 135 00:06:33,050 --> 00:06:34,290 direction as distance. 136 00:06:34,290 --> 00:06:37,470 The whole time, friction is acting against the distance. 137 00:06:37,470 --> 00:06:40,690 So when the force is going in the opposite direction as the 138 00:06:40,690 --> 00:06:42,430 distance, your work is negative. 139 00:06:42,430 --> 00:06:45,440 140 00:06:45,440 --> 00:06:49,500 So another way of thinking of this problem is energy initial 141 00:06:49,500 --> 00:06:56,420 is equal to, or you could say the energy initial plus the 142 00:06:56,420 --> 00:06:58,370 negative work of friction, right? 143 00:06:58,370 --> 00:07:02,090 If we say that this is a negative quantity, then this 144 00:07:02,090 --> 00:07:05,730 is equal to the final energy. 145 00:07:05,730 --> 00:07:07,920 And here, I took the friction and put it on the other side 146 00:07:07,920 --> 00:07:10,410 because I said this is going to be a negative quantity in 147 00:07:10,410 --> 00:07:11,290 the system. 148 00:07:11,290 --> 00:07:13,680 And so you should always just make sure that if you have 149 00:07:13,680 --> 00:07:15,770 friction in the system, just as a reality check, that your 150 00:07:15,770 --> 00:07:18,100 final energy is less than your initial energy. 151 00:07:18,100 --> 00:07:25,500 Our initial energy is, let's just say 38.5 kilojoules. 152 00:07:25,500 --> 00:07:28,290 What is the negative work that friction is doing? 153 00:07:28,290 --> 00:07:29,530 Well it's 500 meters. 154 00:07:29,530 --> 00:07:33,600 And the entire 500 meters, it's always pushing back on 155 00:07:33,600 --> 00:07:36,420 the rider with a force of 60 newtons. 156 00:07:36,420 --> 00:07:37,960 So force times distant. 157 00:07:37,960 --> 00:07:40,690 So it's minus 60 newtons, cause it's going in the 158 00:07:40,690 --> 00:07:44,530 opposite direction of the motion, times 500. 159 00:07:44,530 --> 00:07:49,000 And this is going to equal the ending, oh, no. 160 00:07:49,000 --> 00:07:53,460 This is going to equal the final energy, right? 161 00:07:53,460 --> 00:07:54,030 And what is this? 162 00:07:54,030 --> 00:08:00,100 60 times 500, that's 3,000. 163 00:08:00,100 --> 00:08:01,190 No, 30,000, right. 164 00:08:01,190 --> 00:08:04,975 So let's subtract 30,000 from 38,500. 165 00:08:04,975 --> 00:08:06,490 So let's see. 166 00:08:06,490 --> 00:08:09,580 Minus 30. 167 00:08:09,580 --> 00:08:10,460 I didn't have to do that. 168 00:08:10,460 --> 00:08:11,780 I could have done that in my head. 169 00:08:11,780 --> 00:08:19,990 So that gives us 8,455 joules is equal to the final energy. 170 00:08:19,990 --> 00:08:21,820 And what is all the final energy? 171 00:08:21,820 --> 00:08:24,530 Well by this time, the rider's gotten back to, I guess we 172 00:08:24,530 --> 00:08:25,410 could call the sea level. 173 00:08:25,410 --> 00:08:26,890 So all of the energy is now going to be 174 00:08:26,890 --> 00:08:28,930 kinetic energy, right? 175 00:08:28,930 --> 00:08:30,510 What's the formula for kinetic energy? 176 00:08:30,510 --> 00:08:35,058 It's 1/2 mv squared. 177 00:08:35,058 --> 00:08:36,579 And we know what m is. 178 00:08:36,580 --> 00:08:38,126 The mass of the rider is 90. 179 00:08:38,126 --> 00:08:42,480 So we have this is 90. 180 00:08:42,480 --> 00:08:44,610 So if we divide both sides. 181 00:08:44,610 --> 00:08:45,850 So the 1/2 times 90. 182 00:08:45,850 --> 00:08:48,160 That's 45. 183 00:08:48,160 --> 00:08:50,140 So 8,455 divided by 45. 184 00:08:50,140 --> 00:08:59,540 So we get v squared is equal to 187.9. 185 00:08:59,540 --> 00:09:01,500 And let's take the square root of that and we get the 186 00:09:01,500 --> 00:09:06,690 velocity, 13.7. 187 00:09:06,690 --> 00:09:09,340 So if we take the square root of both sides of this, so the 188 00:09:09,340 --> 00:09:12,900 final velocity is 13.7. 189 00:09:12,900 --> 00:09:14,270 I know you can't read that. 190 00:09:14,270 --> 00:09:17,510 13.7 meters per second. 191 00:09:17,510 --> 00:09:20,960 And this was a slightly more interesting problem because 192 00:09:20,960 --> 00:09:24,480 here we had the energy wasn't completely conserved. 193 00:09:24,480 --> 00:09:27,460 Some of the energy, you could say, was eaten by friction. 194 00:09:27,460 --> 00:09:28,700 And actually that energy just didn't 195 00:09:28,700 --> 00:09:30,080 disappear into a vacuum. 196 00:09:30,080 --> 00:09:32,860 It was actually generated into heat. 197 00:09:32,860 --> 00:09:33,490 And it makes sense. 198 00:09:33,490 --> 00:09:37,930 If you slid down a slide of sandpaper, your pants would 199 00:09:37,930 --> 00:09:40,750 feel very warm by the time you got to the bottom of that. 200 00:09:40,750 --> 00:09:43,400 But the friction of this, they weren't specific on where the 201 00:09:43,400 --> 00:09:45,420 friction came from, but it could have come from the 202 00:09:45,420 --> 00:09:46,420 gearing within the bike. 203 00:09:46,420 --> 00:09:48,550 It could have come from the wind. 204 00:09:48,550 --> 00:09:50,470 Maybe the bike actually skidded a little 205 00:09:50,470 --> 00:09:51,280 bit on the way down. 206 00:09:51,280 --> 00:09:52,190 I don't know. 207 00:09:52,190 --> 00:09:54,290 But hopefully you found that a little bit interesting. 208 00:09:54,290 --> 00:09:57,230 And now you can not only work with conservation of 209 00:09:57,230 --> 00:09:59,950 mechanical energy, but you can work problems where there's a 210 00:09:59,950 --> 00:10:01,820 little bit of friction involved as well. 211 00:10:01,820 --> 00:10:03,380 Anyway, I'll see you in the next video. 212 00:10:03,380 --> 00:00:00,000