- [Instructor] Let's talk about how to handle
a horizontally launched projectile problem.
These, technically speaking, if you already know
how to do projectile problems, there is nothing new,
except that there's one aspect of these problems
that people get stumped by all of the time.
So I'm gonna show you what that is in a minute
so that you don't fall into the same trap.
What we mean by a horizontally launched projectile
is any object that gets launched
in a completely horizontal velocity to start with.
So if something is launched off of a cliff, let's say,
in this straight horizontal direction
with no vertical component to start with,
then it's a horizontally launched projectile.
What could that be?
I mean a boring example, it's just a ball
rolling off of a table.
If you just roll the ball off of the table,
then the velocity the ball has to start off with,
if the table's flat and horizontal,
the velocity of the ball initially would just be horizontal.
So if the initial velocity of the object for a projectile
is completely horizontal, then that object
is a horizontally launched projectile.
A more exciting example.
People do crazy stuff.
Let's say this person is gonna cliff dive or base jump,
and they're gonna be like "whoa, let's do this."
We're gonna do this, they're pumped up.
They're gonna run but they don't jump off the cliff,
they just run straight off of the cliff
'cause they're kind of nervous.
Let's say they run off of this cliff
with five meters per second
of initial velocity, straight off the cliff.
And let's say they're completely crazy,
let's say this cliff is 30 meters tall.
So that's like over 90 feet.
That is kind of crazy.
So 30 meters tall, they launch, they fly through the air,
there's water down here, so they initially went this way,
and they start to fall down,
and they do something like pschhh,
and then they splash in the water,
hopefully they don't hit any boats or fish down here.
That fish already looks like he got hit.
He or she.
Alright, fish over here, person splashed into the water.
We want to know, here's the question you might get asked:
how far did this person go horizontally
before striking the water?
This is a classic problem, gets asked all the time.
And if you were a cliff diver,
I mean don't try this at home,
but if you were a professional cliff diver
you might want to know for this cliff high and this speed
how fast do I have to run in order to avoid
maybe the rocky shore right here
that you might want to avoid.
Maybe there's this nasty craggy cliff bottom here
that you can't fall on.
So how fast would I have to run
in order to make it past that?
Alright, so conceptually what's happening here,
the same thing that happens for any projectile problem,
the horizontal direction is happening
independently of the vertical direction.
And what I mean by that is that the horizontal velocity
evolves independent to the vertical velocity.
Let me get the velocity this color.
So say the vertical velocity,
or the vertical direction is pink,
horizontal direction is green.
This vertical velocity is gonna be changing
but this horizontal velocity is just gonna remain the same.
These do not influence each other.
In other words, this horizontal velocity started at five,
the person's always gonna have five meters per second
of horizontal velocity.
So this horizontal velocity is always gonna be
five meters per second.
The whole trip, assuming this person really is
a freely flying projectile,
assuming that there is no jet pack
to propel them forward and no air resistance.
This person's always gonna have five meters per second
of horizontal velocity up onto the point
right when they splash in the water,
and then at that point there's forces from the water
that influence this acceleration in various ways
that we're not gonna consider.
How about vertically?
Vertically this person starts with no initial velocity.
So this person just ran horizontally straight off the cliff
and then they start to gain velocity.
So they're gonna gain vertical velocity downward
and maybe more vertical velocity
because gravity keeps pulling,
and then even more, this might go off the screen
but it's gonna be really big.
So a lot of vertical velocity,
this should keep getting bigger and bigger and bigger
because gravity's influencing this vertical direction
but not the horizontal direction.
So how do we solve this with math?
Let's write down what we know.
What we know is that horizontally this person started off
with an initial velocity.
V initial in the x, I could have written i for initial,
but I wrote zero for v naught in the x,
it still means initial velocity is five meters per second.
And we don't know anything else in the x direction.
You might think 30 meters is the displacement
in the x direction, but that's a vertical distance.
This is not telling us anything
about this horizontal distance.
This horizontal distance or displacement
is what we want to know.
This horizontal displacement in the x direction,
that's what we want to solve for,
so we're gonna declare our ignorance, write that here.
We don't know how to find it
but we want to know that we do want to find
so I'm gonna write it there.
How about in the y direction, what do we know?
We know that the, alright, now we're gonna use this 30.
You might want to say that delta y is positive 30
but you would be wrong, and the reason is,
this person fell downward 30 meters.
Think about it.
They started at the top of the cliff,
ended at the bottom of the cliff.
It means this person is going to end up
below where they started,
30 meters below where they started.
So this has to be negative 30 meters for the displacement,
assuming you're treating downward as negative
which is typically the convention shows
that downward is negative and leftward is negative.
So if you choose downward as negative,
this has to be a negative displacement.
What else do we know vertically?
Well, for a freely flying object we know
that the acceleration vertically is always gonna be
negative 9.8 meters per second squared,
assuming downward is negative.
Now, here's the point where people get stumped,
and here's the part where people make a mistake.
They want to say that the initial velocity
in the y direction is five meters per second.
I mean people are just dying to stick
these five meters per second into here
because that's the velocity that you were given.
But this was a horizontal velocity.
That's why this is called
horizontally launched projectile motion,
not vertically launched projectile motion.
So think about it.
The initial velocity in the vertical direction here
was zero, there was no initial vertical velocity.
This person was not launched vertically up
or vertically down,
this person was just launched straight horizontally,
and so the initial velocity
in the vertical direction is just zero.
People don't like that.
They're like "hold on a minute."
They're like, this person is gonna start gaining,
alright, this person is gonna start gaining velocity
right when they leave the cliff,
this starts getting bigger and bigger and bigger
in the downward direction.
But that's after you leave the cliff.
We're talking about right as you leave the cliff.
That moment you left the cliff
there was only horizontal velocity,
which means you started with no initial vertical velocity.
So this is the part people get confused by
because this is not given to you explicitly in the problem.
The problem won't say, "Find the distance for a cliff diver
"assuming the initial velocity in the y direction was zero."
Now, they're just gonna say,
"A cliff diver ran horizontally off of a cliff.
"Find this stuff."
And you're just gonna have to know that okay,
if I run off of a cliff horizontally
or something gets shot horizontally,
that means there is no vertical velocity to start with,
I'm gonna have to plug this initial velocity
in the y direction as zero.
So that's the trick.
Don't fall for it now you know how to deal with it.
So we want to solve for displacement in the x direction,
but how many variables we know in the y direction?
I mean we know all of this.
This is good.
But we can't use this to solve directly
for the displacement in the x direction.
We need to use this to solve for the time
because the time is gonna be the same
for the x direction and the y direction.
So I find the time I can plug back in over to there,
because think about it, the time it takes for this trip
is gonna be the time it takes for this trip.
It doesn't matter whether I call it the x direction
or y direction, time is the same for both directions.
In other words, the time it takes for this displacement
of negative 30 is gonna be the time it takes
for this displacement of whatever this is
that we're gonna find.
So let's solve for the time.
Now, how will we do that?
Think about it.
We know the displacement, we know the acceleration,
we know the initial velocity, and we know the time.
But we don't know the final velocity
and we're not asked to find the final velocity,
we don't want to know it.
So let's use a formula that doesn't involve
the final velocity and that would look like this.
So if we use delta y equals
v initial in the y direction times time
plus one half acceleration in the y direction
times time squared.
Alright, now we can plug in values.
My displacement in the y direction is negative 30.
My initial velocity in the y direction is zero.
This is where it would happen, this is where the mistake
would happen, people just really want
to plug that five in over here.
But don't do it, it's a trap.
So, zero times t is just zero
so that whole term is zero.
Plus one half, the acceleration
is negative 9.8 meters per second squared.
And then times t squared, alright, now I can solve for t.
I'm gonna solve for t,
and then I'd have to take the square root of both sides
because it's t squared, and what would I get?
I'd have to multiply both sides by two.
So I get negative 30 meters times two,
and then I have to divide both sides
by negative 9.8 meters per second squared, equals,
notice if you would have forgotten
this negative up here for negative 30,
you come down here, this would be a positive up top.
You'd have a negative on the bottom.
You'd have to plug this in, you'd have to try to take
the square root of a negative number.
Your calculator would have been all like,
"I don't know what that means,"
and you're gonna be like, "Er, am I stuck?"
So you'd start coming back here probably and be like,
"Let's just make stuff positive and see if that works."
It would work because look at these negatives canceled
but it's best to just know
what you're talking about in the first place.
So be careful: plug in your negatives
and things will work out alright.
So if you solve this you get
that the time it took is 2.47 seconds.
It's actually a long time.
It might seem like you're falling for a long time
sometimes when you're like jumping off of a table,
jumping off of a trampoline,
but it's usually like a fraction of a second.
This is actually a long time, two and a half seconds
of free fall's a long time.
So we could take this, that's how long
it took to displace by 30 meters vertically,
but that's gonna be how long it took to displace
this horizontal direction.
We can use the same formula.
We can say that well, if delta x equals
v initial in the x direction,
I'm just using the same formula but in the x direction,
plus one half ax t squared.
So the same formula as this just in the x direction.
Delta x is just dx, we already gave that a name,
so let's just call this dx.
So I'm gonna scooch this equation over here.
Dx is delta x, that equals the initial velocity
in the x direction, that's five.
Alright, this is really five.
In the x direction the initial velocity
really was five meters per second.
How about the initial time?
Oh sorry, the time, there is no initial time.
The time here was 2.47 seconds.
This was the time interval.
The time between when the person jumped,
or ran off the cliff,
and when the person splashed in the water was 2.4,
let me erase this, 2.47 seconds.
So 2.47 seconds, and this comes over here.
How about this ax?
This ax is zero.
Remember there's nothing compelling this person
to start accelerating in x direction.
If they've got no jet pack, there is no air resistance,
there is no reason this person
is gonna accelerate horizontally,
they maintain the same velocity the whole way.
So what do we get?
If we solve this for dx, we'd get that dx
is about 12.4, I believe.
Let's see, I calculated this.
12.4-ish meters.
Okay, so if these rocks down here
extend more than 12 meters,
you definitely don't want to do this.
I mean if it's even close
you probably wouldn't want do this.
In fact, just for safety don't try this at home,
leave this to professional cliff divers.
I'm just saying if you were one and you wanted to calculate
how far you'd make it, this is how you would do it.
So, long story short, the way you do this problem
and the mistakes you would want to avoid are:
make sure you're plugging your negative displacement
because you fell downward,
but the big one is make sure you know
that the initial vertical velocity is zero
because there is only horizontal velocity to start with.
That's not gonna be given explicitly,
you're just gonna have to provide that on your own
and your own knowledge of physics.